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17 Oct 2020, 13:19
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Difficulty:
95%
(hard)
Question Stats:
37% (03:09) correct
63%
(02:59)
wrong
based on 41
sessions
History
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In its initial “trip” starting at point X in the circuit pictured above, a glip jumps to A to B and back to X, then to D and back to X. Each successive trip follows the same pattern of jumps, starting with a jump to the next point clockwise (in this case, B) around the circuit. After jump 472, the glip will be at point
(A) X
(B) A
(C) C
(D) D
(E) E
Attachment:
2020-10-18_00-18-04.png [ 12.45 KiB | Viewed 1352 times ]
17 Oct 2020, 21:11
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Bunuel
In its initial “trip” starting at point X in the circuit pictured above, a glip jumps to A to B and back to X, then to D and back to X. Each successive trip follows the same pattern of jumps, starting with a jump to the next point clockwise (in this case, B) around the circuit. After jump 472, the glip will be at point
(A) X
(B) A
(C) C
(D) D
(E) E
Attachment:
2020-10-18_00-18-04.png
If we count the successive jumps starting with a jump to the point B, in 26th jump, glimp will be again in point B.
1st - B
2nd - C
3rd - X
4th - E
5th - X
6th - C
...
11th - D
...
16th - E
...
21th - A
...
26th - B
In 26*18=468th jump it will also be in point B.
469th - C
470th - X
471st - D
472nd - X
In 472th jump it will be in point X. A)
17 Oct 2020, 21:39
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jump to A=1
jump to X =3
jump to D =4
jump to X = 5
jump to B ---
jump to X = 8
jump to E ---
jump to X =10
so from the above pattern, the glip is back at X every 5n jump or every 5n +3 jump
we are asked to find out where the glip will be after 472nd jump , i.e. at 473rd jump
473 can be written in the form of 5n+3, so the glip will be at X
jump to X =3
jump to D =4
jump to X = 5
jump to B ---
jump to X = 8
jump to E ---
jump to X =10
so from the above pattern, the glip is back at X every 5n jump or every 5n +3 jump
we are asked to find out where the glip will be after 472nd jump , i.e. at 473rd jump
473 can be written in the form of 5n+3, so the glip will be at X
