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Bunuel
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Many thanks!!!

But I dont really get the step, to multiply with 5y

Could you please explain it to me.

Thanks!
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NYC5648
Many thanks!!!

But I dont really get the step, to multiply with 5y

Could you please explain it to me.

Thanks!

We are told that "the maximum marks of each subject is the same", say it's y, then the sum of the marks in all 5 subjects will be y+y+y+y+y=5y.

Hope it's clear.
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Hi bunnel

can you suggest any material for ratio and proportions. I have completed ratio and proportions in manhattan word translations, but still i need some extra practice

Thanks
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Hi bunnel

can you suggest any material for ratio and proportions. I have completed ratio and proportions in manhattan word translations, but still i need some extra practice

Thanks

I can think of no material on this subject though below are some questions to practice:
PS questions on Fractions/Ratios/Decimals: search.php?search_id=tag&tag_id=36
DS questions on Fractions/Ratios/Decimals: search.php?search_id=tag&tag_id=57

Hope it helps.
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took x as a percentage of score in an exam

(4x+5x+6x+7x+8x)5 =72 = avg percentage
6x=72
x = 12

therefore marks are 48%, 60% and so on and only the one value 48% is below the passing threshold of 50%. Hence, A.
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NYC5648
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Many thanks.
Have a great Sunday!

LET MAX MARKS BE Y

then (4+5+6+7+8)x=0.72*5y
=> 30x=3.6y
=> x=36y/300=3y/25
hence

4x= 4*3y/25=12y/25--> fail
5x--> pass
as all other scores are greater than 5x hence he passed in all

hence failed in 1 subject

option A
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

*New project from GMAT Club!!! Check HERE

All DS Fractions/Ratios/Decimals questions: search.php?search_id=tag&tag_id=36
All PS Fractions/Ratios/Decimals questions: search.php?search_id=tag&tag_id=57
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NYC5648
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Many thanks.
Have a great Sunday!


For ratio and proportion questions, We can always check at first for plugging in values.

Let us assume that for each exam the max score is 100. So total max score in 5 exams is 500
where as Roger scored 72% of 500 which is 360

360 is total marks scored by Roger which is nothing but some of sum of his scores in all subjects

so we have 4a+5a+6a+7a+8a = 360 where "a" is any positive integer, solving for "a", we get 30a= 360 ----> a=12

4a= 48 < 50 and in rest all exams he passed so ans should be A
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NYC5648
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Many thanks.
Have a great Sunday!

Total sum of scores is 30x

Total sum of scores is also 720

720/30 = 12 = x

So then, we can start with the first and it will give 48, fail
Next is obviously 60 pass, so only 1 fail

Hence A

Hope it helps!
Cheers
J :)
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In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Given: A:B:C:D:E=4x:5x:6x:7x:8x, for some multiple x. Assume the maximum marks of each subject to be y, so the the maximum marks of ALL 5 subjects will be 5y.

So, we have that \(4x+5x+6x+7x+8x=\frac{72}{100}*5y\) --> \(30x=\frac{72*5}{100}*y\) --> \(x=\frac{12}{100}*y\). \(4x=\frac{48}{100}*y\) and \(5x=\frac{60}{100}*y\), so in subject A Roger scored 48% (less than 50%) and in subject B 60% (more than 50%). Obviously in all other subjects Rogers scores will be higher than 50%.

Roger failed in only one subject A.

Answer: A.

P.S. Please post PS questions in the PS subforum: gmat-problem-solving-ps-140/ and DS questions in the DS subforum: gmat-data-sufficiency-ds-141/

No posting of PS/DS questions is allowed in the main Math forum.

Bunuel - Could you walk me through how you reduced the fraction above (highlighted in blue)
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Bunuel
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Given: A:B:C:D:E=4x:5x:6x:7x:8x, for some multiple x. Assume the maximum marks of each subject to be y, so the the maximum marks of ALL 5 subjects will be 5y.

So, we have that \(4x+5x+6x+7x+8x=\frac{72}{100}*5y\) --> \(30x=\frac{72*5}{100}*y\) --> \(x=\frac{12}{100}*y\). \(4x=\frac{48}{100}*y\) and \(5x=\frac{60}{100}*y\), so in subject A Roger scored 48% (less than 50%) and in subject B 60% (more than 50%). Obviously in all other subjects Rogers scores will be higher than 50%.

Roger failed in only one subject A.

Answer: A.

P.S. Please post PS questions in the PS subforum: gmat-problem-solving-ps-140/ and DS questions in the DS subforum: gmat-data-sufficiency-ds-141/

No posting of PS/DS questions is allowed in the main Math forum.

Bunuel - Could you walk me through how you reduced the fraction above (highlighted in blue)

\(30x=\frac{72*5}{100}*y=\frac{(6*12)*5}{100}*y\) --> reduce by 30=6*5: \(x=\frac{12}{100}*y\) --> multiply by 4: \(4x=\frac{48}{100}*y\).

Hope it's clear.
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Option A.
Let the marks be 4x,5x,6x,7x and 8x.
Total=30x
Avg.=6x
Now 6x=72
X=12
On calculating Subject marks,we get 48,60,72,84 & 96.
Only one subject is <50.

Posted from my mobile device
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monalimishra
I did this by picking numbers.
Say the max mark in each subject is 100.
Then I can directly know that Roger scored 40,50,60,70,80.
Since passing mark is 50% of max mark => passing mark = 50.
Thus Roger failed in only 1 subject, where he scored 40.

Answer A.

Though the answer A is correct, the calculations are wrong :(

If we consider 40,50,60,70,80 as the scores, then the average comes up 60%
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Hi,
Is my logic correct.

what i understood was 72% score implies, 72% of max that is 100%
and since he got 72% in the ratios 4 5 6 7 8 therefore he got 48% of max marks in A. which is less that 50% if max marks.
hence he failed in 1 subject.
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[4x+5x+6x+7x+8x]/5 = 72
30x=360
x=12

4(12) = 48, which is below 50, thus we have 1 exam that he failed.
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NYC5648
In last examination Roger scored marks in each of 5 subjects in the following ratio 4:5:6:7:8 and got an overall score of 72%. If 50% of the maximum marks is passing and the maximum marks of each subject is the same, in how many subjects did Roger fail?

A. 1
B. 2
C. 3
D. 4
E. 5

Many thanks.
Have a great Sunday!

let each subject be max 100 marks
so total marks max ; 500
and passing marks ; 50 marks for each subject
he scored ; 500* .72 ; 360 marks
so his avg per subject must be 360/30 ; 12 marks
4:5:6:7:8 ; we see that at 4*12 ; 48 marks is 1 subject where he has scored <50 %
OPTION A ; 1
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