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# In Quadrilateral WXYZ, is XY perpendicular to YZ?

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Manager
Joined: 25 Aug 2004
Posts: 166
Location: MONTREAL

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16 Sep 2005, 07:18
1
11
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Difficulty:

75% (hard)

Question Stats:

47% (01:01) correct 53% (00:46) wrong based on 288 sessions

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In Quadrilateral WXYZ, is XY perpendicular to YZ?

(1) WXY is a right angle

(2) WZY is a right angle
Senior Manager
Joined: 30 Oct 2004
Posts: 284

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16 Sep 2005, 07:28
I get D) Either is sufficient to answer they are not perpendicular.
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-Vikram

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Joined: 15 Jul 2005
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Updated on: 16 Sep 2005, 14:26
vikramm wrote:
I get D) Either is sufficient to answer they are not perpendicular.

How do you conclude XY is not perpendicular to YZ, by either of those statements??

... oops, maybe not also!

Originally posted by chets on 16 Sep 2005, 07:39.
Last edited by chets on 16 Sep 2005, 14:26, edited 1 time in total.
Senior Manager
Joined: 04 May 2005
Posts: 274
Location: CA, USA

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16 Sep 2005, 10:05
E

get a piece of paper (rectangle), tear it along the diagnal line to get two right triangles. Try to make a quad with their two right sides - you will get any number of non-rectangle quad (with two 90degree corners)
Intern
Joined: 25 Jan 2005
Posts: 17
Location: Chicago

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16 Sep 2005, 11:36
Precisely, E it is.

Sum of 4 angles of a quad is 360. Two being 90, we cant say anything about the remaining two.
Or
Intern
Joined: 16 Jun 2005
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16 Sep 2005, 14:40
mbassmbass04 wrote:
In Quadrilateral WXYZ, is XY perpendicular to YZ?

(1) WXY is a right angle

(2) WZY is a right angle

I think i should be C. If two opposite angles are 90 degrees in a quad, it has to be rectangle.
What is OA?
Intern
Joined: 19 Aug 2005
Posts: 41

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16 Sep 2005, 21:31
3
Agree with qpoo now. understood my mistake. it must be E. thanks qpoo. that was a great help...

i have drawn a quadrilateral to prove that. hope it'll help. [/img]
Attachments

WXYZ.doc [19 KiB]

Manager
Joined: 25 Aug 2004
Posts: 166
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17 Sep 2005, 10:59
It looks like the OA is E.

I personaly choose C first.

This is what is written in the answer...

If you choose to draw the quadrilateral, you must realize that you don't know whether it's regular shape as a parallelogram or whether it's a stranger shape, also when you label points do so clockwise. Statement 1 only tells about on angle so it's insufficient since the others could be anything. Statement 2 has the same problem. Together the statements don't resolve it because it could be a square or it could be a shape with angles 90,90,110 and 80 (try to draw this you will see its possible)
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23 Aug 2016, 21:57
3
Let me spell it via a diagram:

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Citius, Altius, Fortius

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21 Sep 2017, 10:31
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Re: In Quadrilateral WXYZ, is XY perpendicular to YZ? &nbs [#permalink] 21 Sep 2017, 10:31
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