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Re: In the diagram above, the line y = 4 is the perpendicular bisector of [#permalink]

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26 May 2011, 00:25

Refer to diagram:

Attachment:

SOLN.JPG [ 13.1 KiB | Viewed 4377 times ]

y=4 is perpendicular bisector of JK Hence distance between Point J and line y = 6 = distance between line y and point K. Point K(6,-2) Distance between point K and origin is 6^2+2^2= 2\sqrt{10}

OA B.

Please let me know the OA.
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Re: In the diagram above, the line y = 4 is the perpendicular bisector of [#permalink]

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08 May 2015, 08:41

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Re: In the diagram above, the line y = 4 is the perpendicular bisector of [#permalink]

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14 Nov 2016, 09:00

Answer:B 1- We have J(6,10) and the line y = 4 is the perpendicular bisector of segment JK ⇒ Intersection point of the two lines is the midpoint M(6,4) ⇒ k is (6,-2) 2- Taking the point on the X-axis L(6,0) ⇒ we have a right triangle OLK with O(0,0), L(6,0), and K(6,-2) Finally the hypotenuse OK^2=OL^2+LA^2=6^2+2^2=36+4=40 ⇒ OK=sqrt(40)=2sqrt(10)