GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 20 Jun 2018, 21:50

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

In the figure above, CD is tangent to the circle with center A. If the

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Expert Post
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 46214
In the figure above, CD is tangent to the circle with center A. If the [#permalink]

Show Tags

New post 01 Mar 2017, 05:30
00:00
A
B
C
D
E

Difficulty:

  85% (hard)

Question Stats:

55% (02:55) correct 45% (01:52) wrong based on 108 sessions

HideShow timer Statistics

Image
In the figure above, CD is tangent to the circle with center A. If the length of BE is 10 and the length of CE is 2, what is the length of CD?

A. 2
B. 8/3
C. 3
D. 10/3
E. 4

Attachment:
CD_.PNG
CD_.PNG [ 12 KiB | Viewed 1858 times ]

_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

1 KUDOS received
Director
Director
User avatar
P
Joined: 05 Mar 2015
Posts: 971
In the figure above, CD is tangent to the circle with center A. If the [#permalink]

Show Tags

New post 01 Mar 2017, 08:59
1
2
Bunuel wrote:
Image
In the figure above, CD is tangent to the circle with center A. If the length of BE is 10 and the length of CE is 2, what is the length of CD?

A. 2
B. 8/3
C. 3
D. 10/3
E. 4

Attachment:
The attachment CD_.PNG is no longer available



Please follow below fig.

Since AB = AC = radius
thus from pythagorian triplet , in triangle ABE AB=8 and AE =6 (as AC=6+2=8=radius AB)
Now both triangles are AAA similar (since tangent to circle makes 90 deg with circle)
we can write AB/ CD = AE/EC
putting values
8/CD= 6/2
thus CD= 8/3

Ans B
Attachments

CD_.PNG
CD_.PNG [ 12.36 KiB | Viewed 1494 times ]

Intern
Intern
avatar
B
Joined: 07 Sep 2012
Posts: 8
GMAT 1: 650 Q50 V28
GPA: 2.8
WE: Operations (Retail)
Re: In the figure above, CD is tangent to the circle with center A. If the [#permalink]

Show Tags

New post 01 Mar 2017, 10:59
Image


Sent from my iPhone using GMAT Club Forum mobile app
Intern
Intern
avatar
B
Joined: 20 Dec 2014
Posts: 37
GMAT ToolKit User CAT Tests
Re: In the figure above, CD is tangent to the circle with center A. If the [#permalink]

Show Tags

New post 04 Feb 2018, 04:31
rohit8865 wrote:
Bunuel wrote:
Image
In the figure above, CD is tangent to the circle with center A. If the length of BE is 10 and the length of CE is 2, what is the length of CD?

A. 2
B. 8/3
C. 3
D. 10/3
E. 4

Attachment:
CD_.PNG



Please follow below fig.

Since AB = AC = radius
thus from pythagorian triplet , in triangle ABE AB=8 and AE =6 (as AC=6+2=8=radius AB)
Now both triangles are AAA similar (since tangent to circle makes 90 deg with circle)
we can write AB/ CD = AE/EC
putting values
8/CD= 6/2
thus CD= 8/3

Ans B


the insight on the Pythagoras triplet would save a lot of time.. i got it correct but took about twice the time to complete the question that the average,
Would have finished in 2 mins if realized the triplet in play...
noted it as one of the things to do for Geometry questions
_________________

Kindly press "+1 Kudos" to appreciate :)

Senior Manager
Senior Manager
avatar
G
Joined: 31 Jul 2017
Posts: 368
Location: Malaysia
WE: Consulting (Energy and Utilities)
Re: In the figure above, CD is tangent to the circle with center A. If the [#permalink]

Show Tags

New post 05 Feb 2018, 00:59
Bunuel wrote:
Image
In the figure above, CD is tangent to the circle with center A. If the length of BE is 10 and the length of CE is 2, what is the length of CD?

A. 2
B. 8/3
C. 3
D. 10/3
E. 4

Attachment:
CD_.PNG


Given,

\(r^2 + (r-2)^2 = 100\)
\(r = 8.\)

Triangle ABE is Similar to Triangle CDE.

\(\frac{8}{CD} = \frac{6}{2}\)
\(CD = \frac{8}{3}\)
_________________

If my Post helps you in Gaining Knowledge, Help me with KUDOS.. !!

Re: In the figure above, CD is tangent to the circle with center A. If the   [#permalink] 05 Feb 2018, 00:59
Display posts from previous: Sort by

In the figure above, CD is tangent to the circle with center A. If the

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.