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05 Sep 2017, 23:40
Kudos
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C
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Difficulty:
5%
(low)
Question Stats:
88% (01:05) correct
12%
(01:23)
wrong
based on 57
sessions
History
Date
Time
Result
Not Attempted Yet
In the figure above, if CAB is a right angle, then x =
(A) 38
(B) 40
(C) 42
(D) 45
(E) 48
Attachment:
2017-09-06_1033_002.png [ 7.53 KiB | Viewed 2595 times ]
06 Sep 2017, 04:03
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Bunuel
Let the point on BC from A be at D..
Now angle X = angle CAB - angle CAD= 90-angle CAD
In ∆ACD, angle C + angle CAD =90 or angle CAD=90-42
So x = 90-(90-42)=42
C
11 Sep 2017, 10:59
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Bunuel
Let the vertex of the right angle on BC be D. We see that angle DAC = 180 - 90 - 42 = 48.
Since angle CAB = 90 and angle DAC = 48, angle BAD = x = 90 - 48 = 42.
Answer: C
