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# In the figure above, if the radii of the two smaller circles is each

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Math Expert
Joined: 02 Sep 2009
Posts: 50058
In the figure above, if the radii of the two smaller circles is each  [#permalink]

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14 Nov 2017, 01:08
00:00

Difficulty:

35% (medium)

Question Stats:

71% (01:25) correct 29% (01:38) wrong based on 20 sessions

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In the figure above, if the radii of the two smaller circles is each equal to 1/3 of the radius of the larger circle, then the ratio (area of the shaded region)/(area of the larger circle) is equal to

(A) 8/9
(B) 7/9
(C) 2/3
(D) 4/9
(E) 1/3

Attachment:

2017-11-14_1156_001.png [ 6.74 KiB | Viewed 366 times ]

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Re: In the figure above, if the radii of the two smaller circles is each  [#permalink]

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14 Nov 2017, 02:09
Bunuel wrote:

In the figure above, if the radii of the two smaller circles is each equal to 1/3 of the radius of the larger circle, then the ratio (area of the shaded region)/(area of the larger circle) is equal to

(A) 8/9
(B) 7/9
(C) 2/3
(D) 4/9
(E) 1/3

Attachment:
2017-11-14_1156_001.png

Question: (area of the shaded region)/(area of the larger circle) = ?

Let, Radius of bigger circle =3
i.e. Radius of each smaller circle = 1

Area of Shaded Region = Area of Bigger circle - Area of two smaller circles = π(3)^2 - 2*π(1)^2 = 9π-2π = 7π
Area of Larger Circle = π(3)^2 = 9π

(area of the shaded region)/(area of the larger circle) = 7π/9π = 7/9

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Re: In the figure above, if the radii of the two smaller circles is each &nbs [#permalink] 14 Nov 2017, 02:09
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