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In the figure above, O is the center of the circle. If the area of tri

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In the figure above, O is the center of the circle. If the area of tri  [#permalink]

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New post 11 Jan 2019, 00:12
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In the figure above, O is the center of the circle. If the area of triangle XOY is 25, what is the area of the circle?


A. \(25\pi\)

B. \(25\pi \sqrt{2}\)

C. \(50\pi\)

D. \(50\pi \sqrt{3}\)

E. \(625\pi\)


Attachment:
2019-01-11_1159.png
2019-01-11_1159.png [ 18.15 KiB | Viewed 246 times ]

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In the figure above, O is the center of the circle. If the area of tri  [#permalink]

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New post Updated on: 13 Jan 2019, 07:20
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My answer is C
Area of triangle is 1/2*B*H=25
Here B=H being radius)
therefore B=H=Sqrt 50

Area of circle = Pi(r)^2== Pi(sqrt 50)^2=pi(5sqrt2)^2= 50pi

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Originally posted by carajatarora on 11 Jan 2019, 00:18.
Last edited by carajatarora on 13 Jan 2019, 07:20, edited 1 time in total.
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Re: In the figure above, O is the center of the circle. If the area of tri  [#permalink]

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New post 11 Jan 2019, 00:22
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carajatarora wrote:
My answer is C
Area of triangle is 1/2*B*H=25
Here B=H being radius)
therefore B=H=Sqrt 50

Area of circle = Pi(r)^2== Pi(sqrt 50)^2=pi(5sqrt2)^2= 50pi


Totally nailed it.

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Re: In the figure above, O is the center of the circle. If the area of tri  [#permalink]

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New post 11 Jan 2019, 02:12
Bunuel wrote:
Image

In the figure above, O is the center of the circle. If the area of triangle XOY is 25, what is the area of the circle?


A. \(25\pi\)

B. \(25\pi \sqrt{2}\)

C. \(50\pi\)

D. \(50\pi \sqrt{3}\)

E. \(625\pi\)





Attachment:
2019-01-11_1159.png




radius = x^2 = 25*2 = sqrt 50

area of circle
50*pi
imoc
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In the figure above, O is the center of the circle. If the area of tri  [#permalink]

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New post 11 Jan 2019, 03:40
If the area of triangle XOY = 25, 1/2 b * h = 50

in this case b*h will be r^2
Therefore r^2 = 50

Area of circle= pi r^2
Answer C \(50\pi\)
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Re: In the figure above, O is the center of the circle. If the area of tri  [#permalink]

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New post 11 Jan 2019, 11:03
Area of triangle XOY= 0.5*OX*OY
But OX=OY=radius of circle=r
So, 0.5*r*r=25
r^2=50

Area of circle = pi*r^2=pi*50
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Re: In the figure above, O is the center of the circle. If the area of tri &nbs [#permalink] 11 Jan 2019, 11:03
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