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# In the figure above, radius OB has a length of 4. What is the area of

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Joined: 02 Sep 2009
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In the figure above, radius OB has a length of 4. What is the area of  [#permalink]

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17 Jan 2019, 02:57
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00:00

Difficulty:

35% (medium)

Question Stats:

71% (01:18) correct 29% (01:13) wrong based on 28 sessions

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In the figure above, radius OB has a length of 4. What is the area of triangle ABC?

A 4
B 8
C 12
D 16
E 20

Attachment:

2019-01-17_1455.png [ 11.37 KiB | Viewed 332 times ]

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Re: In the figure above, radius OB has a length of 4. What is the area of  [#permalink]

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17 Jan 2019, 03:02
CO is the height = radius = 4.

AB is the base = diameter = 8.

Area = 1/2*b*h = 16.

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Re: In the figure above, radius OB has a length of 4. What is the area of  [#permalink]

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17 Jan 2019, 06:08
Bunuel wrote:

In the figure above, radius OB has a length of 4. What is the area of triangle ABC?

A 4
B 8
C 12
D 16
E 20

Attachment:
2019-01-17_1455.png

area of the triangle would be

0.5 * 8 * 4
= 16
IMO D
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In the figure above, radius OB has a length of 4. What is the area of  [#permalink]

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17 Jan 2019, 10:18
Bunuel wrote:

In the figure above, radius OB has a length of 4. What is the area of triangle ABC?

A 4
B 8
C 12
D 16
E 20

Attachment:
2019-01-17_1455.png

AB = 2*4 = 8

Hence
(AC)2 + (BC)2 = (AB)2

Hence AC = \sqrt{32} and BC = \sqrt{32}

hence area =1/2 * \sqrt{32} * \sqrt{32}

= 16 (D)
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In the figure above, radius OB has a length of 4. What is the area of   [#permalink] 17 Jan 2019, 10:18
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