HKD1710 wrote:

In the figure above, square CDEF has area 4. What is the area of △ ABF?

(A) 2\(\sqrt{2}\)

(B) 2\(\sqrt{3}\)

(C) 4

(D) 3\(\sqrt{3}\)

(E) 6

First let us calculate the side CF through the given area of square

side becomes 2

After this triangle CFB will be a 30 60 90 triangle

From here we can get the corresponding side FB as 2 \(\sqrt{3}\)

Now since △ ABF, is an isosceles triangle, the height and base will be equal

1/2 * 2 \(\sqrt{3}\) * 2 \(\sqrt{3}\)

6

E

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