HKD1710 wrote:
In the figure above, square CDEF has area 4. What is the area of △ ABF?
(A) 2\(\sqrt{2}\)
(B) 2\(\sqrt{3}\)
(C) 4
(D) 3\(\sqrt{3}\)
(E) 6
First let us calculate the side CF through the given area of square
side becomes 2
After this triangle CFB will be a 30 60 90 triangle
From here we can get the corresponding side FB as 2 \(\sqrt{3}\)
Now since △ ABF, is an isosceles triangle, the height and base will be equal
1/2 * 2 \(\sqrt{3}\) * 2 \(\sqrt{3}\)
6
E
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