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17 Jan 2019, 23:38
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In the figure above, the area of square ABCD is half the area of rectangle AEFC. What is the ratio of AC to BE?
A 1/4
B 1/3
C 1/2
D 1/1
E 2/1
Attachment:
2019-01-18_1036.png [ 4.42 KiB | Viewed 2603 times ]
Archit3110
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18 Jan 2019, 04:53
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Bunuel
area of square = 4 ; rectangle = 8
we can say side of square = 2 and rectangle l=4 and breadth = side of square = 2
so the part AC= 2 and BE = AE-AB = 4-2 = 2
so ratio : 2/2 ; 1/1 IMO D
Arro44
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18 Mar 2019, 06:07
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The question basically tells us that the rectangle is exactly twice as big as the square. Thus we can imagine the rectangle consists of two squares the size of our initial square. Hence, the distance of AB is the exact same as BE.
This one can be solved without a single calculation.
This one can be solved without a single calculation.
