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In the figure above, the area of the shaded region is

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In the figure above, the area of the shaded region is  [#permalink]

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New post 13 Dec 2017, 21:13
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Question Stats:

81% (01:10) correct 19% (01:18) wrong based on 73 sessions

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Re: In the figure above, the area of the shaded region is  [#permalink]

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New post 13 Dec 2017, 22:09
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B.

Assume y-axis as the base and x-axis as height and apply 1/2*base*height.

1/2*4*6=12

Alternatively, draw a quadilateral (0,6) (0,0) (6,0) (6,8) and find area of unshaded portions and reduce from the area of the rectangle.

Area of shaded = area of rectangle - area of unshaded

Area unshaded = 1/2*base*height (for the smaller triangle) + 1/2*base*height (for bigger triangle)

Unshaded are = 1/2*6*4 +1/2*6*8 = 12+24 = 36

Total area = 6*8 =48

Shaded area = 48-36 = 12


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Re: In the figure above, the area of the shaded region is  [#permalink]

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New post 13 Dec 2017, 22:33
Is it 12? the height of the triangle can be taken as 6 because one vertex of triangle is at (6,8) and if we draw a line from that vertex to y-axis the height will be 6...the base will be 4 so are will be 1/2(6)(4) = 12
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Re: In the figure above, the area of the shaded region is  [#permalink]

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New post 01 May 2019, 02:10
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Re: In the figure above, the area of the shaded region is   [#permalink] 01 May 2019, 02:10
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