In the figure, BD and CD are angular bisectors of

Question

In the figure, BD and CD are angular bisectors of <B and <C in an equilateral triangle ABC. What is the ratio of the area polygon ABDC to the area of triangle BDC?
A) 1:2
B) 2:3
C) 3:2
D) 2:1
E) 3:1

PareshGmat · Answer

Join point A to point D

riangle  ABD =  	riangle  ACD =  	riangle  BDC

Area polygon ABDC = 2 times Area  	riangle  BDC

Ratio = 2:1

Answer = D

ThiruN · Answer

How do we come to the conclusion that △ ABD = △ ACD = △ BDC?

kaiserkaran · Answer

hi,
 we know that BD and CD are angular bisectors and from the figure we know they meet at point D, which is basically the incenter.

If an angle bisector is drawn from A it meets at D as show in the previous post.

if u find the angles for all the points of both the triangles u will find that the bigger triangle gets broken down to 3 parts which are equal to each other.

bumpbot · Answer

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In the figure, BD and CD are angular bisectors of <B and <C in an

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