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In the figure given below, ABCD is a rectangle and GB=DH=2HC

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In the figure given below, ABCD is a rectangle and GB=DH=2HC  [#permalink]

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New post Updated on: 04 Aug 2018, 23:30
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In the figure given below, ABCD is a rectangle and GB=DH=2HC, what is the area (in sq. in.) of the shaded region if AD=1 in. and AB=3 in.

A) 1 \(in.^2\)
B) 1.5 \(in.^2\)
C) 2 \(in.^2\)
D) 2.5 \(in.^2\)
E) 3 \(in.^2\)

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Originally posted by souvonik2k on 01 Mar 2018, 08:40.
Last edited by souvonik2k on 04 Aug 2018, 23:30, edited 1 time in total.
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Re: In the figure given below, ABCD is a rectangle and GB=DH=2HC  [#permalink]

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New post 01 Mar 2018, 22:17
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souvonik2k wrote:
In the figure given below, ABCD is a rectangle and GB=DH=2HC, what is the area (in sq. in.) of the shaded region if AD=1 in. and AB=3 in.

A) 1 \(in.^2\)
B) 1.5 \(in.^2\)
C) 2 \(in.^2\)
D) 2.5 \(in.^2\)
E) 3 \(in.^2\)


hi..
the ratio of sides \(DH:HC = 2:1\) so DH = 2
area of parallelogram DHBF = \(2*1=2\)

Area of shaded region is HALF of this parallelogram.
so area of shaded region is \(\frac{2}{2}=1\)
A
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3) effects of arithmetic operations : https://gmatclub.com/forum/effects-of-arithmetic-operations-on-fractions-269413.html


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Re: In the figure given below, ABCD is a rectangle and GB=DH=2HC &nbs [#permalink] 01 Mar 2018, 22:17
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In the figure given below, ABCD is a rectangle and GB=DH=2HC

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