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# In the figure given below, ABCD is a rectangle and GB=DH=2HC

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Status: Preparing for GMAT
Joined: 25 Nov 2015
Posts: 1043
Location: India
GPA: 3.64
In the figure given below, ABCD is a rectangle and GB=DH=2HC  [#permalink]

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Updated on: 05 Aug 2018, 00:30
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74% (03:21) correct 26% (03:12) wrong based on 32 sessions

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In the figure given below, ABCD is a rectangle and GB=DH=2HC, what is the area (in sq. in.) of the shaded region if AD=1 in. and AB=3 in.

A) 1 $$in.^2$$
B) 1.5 $$in.^2$$
C) 2 $$in.^2$$
D) 2.5 $$in.^2$$
E) 3 $$in.^2$$

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Originally posted by souvonik2k on 01 Mar 2018, 09:40.
Last edited by souvonik2k on 05 Aug 2018, 00:30, edited 1 time in total.
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Joined: 02 Aug 2009
Posts: 7984
Re: In the figure given below, ABCD is a rectangle and GB=DH=2HC  [#permalink]

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01 Mar 2018, 23:17
1
souvonik2k wrote:
In the figure given below, ABCD is a rectangle and GB=DH=2HC, what is the area (in sq. in.) of the shaded region if AD=1 in. and AB=3 in.

A) 1 $$in.^2$$
B) 1.5 $$in.^2$$
C) 2 $$in.^2$$
D) 2.5 $$in.^2$$
E) 3 $$in.^2$$

hi..
the ratio of sides $$DH:HC = 2:1$$ so DH = 2
area of parallelogram DHBF = $$2*1=2$$

Area of shaded region is HALF of this parallelogram.
so area of shaded region is $$\frac{2}{2}=1$$
A
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Re: In the figure given below, ABCD is a rectangle and GB=DH=2HC   [#permalink] 01 Mar 2018, 23:17
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