souvonik2k wrote:

In the figure given below, ABCD is a rectangle and GB=DH=2HC, what is the area (in sq. in.) of the shaded region if AD=1 in. and AB=3 in.

A) 1 \(in.^2\)

B) 1.5 \(in.^2\)

C) 2 \(in.^2\)

D) 2.5 \(in.^2\)

E) 3 \(in.^2\)

hi..

the ratio of sides \(DH:HC = 2:1\) so DH = 2

area of parallelogram DHBF = \(2*1=2\)

Area of shaded region is HALF of this parallelogram.

so area of shaded region is \(\frac{2}{2}=1\)

A

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