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In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD =
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09 Oct 2018, 00:36
Question Stats:
88% (01:17) correct 12% (01:11) wrong based on 49 sessions
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Re: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD =
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09 Oct 2018, 00:48
Bunuel wrote: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD = (A) 12 (B) 13 (C) 15 (D) 17 (E) 24 From the measure of various sites of triangle ABC, we can see that it is a right angle triangle whose right angle is at Angle B. Applying Pythagoras theorem to triangle ABD: we can find the measure of AD. AD^2=AB^2 + BD^2 AD^2= 8*8 + 15*15 AD=17, hence option D is the correct one.



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Re: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD =
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09 Oct 2018, 06:11
How can we assume that the triangle is right angled triangle. Neither the angle is given in the figure nor it is said "Drawn to Scale" Experts please help



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Re: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD =
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09 Oct 2018, 06:30



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Re: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD =
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09 Oct 2018, 06:33
Ah missed it. Thank you very much for the explanation Bunuel



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Re: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD =
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09 Oct 2018, 06:41
Bunuel wrote: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD = (A) 12 (B) 13 (C) 15 (D) 17 (E) 24 \(AB = 8\) & \(BD = 15\) in the right Angled Triangle.. SO, Hypotenuse \(AD = 17\) , following Pythagorean triple (8, 15, 17) , Answer must be (D)
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Re: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD =
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09 Oct 2018, 08:29
Bunuel wrote: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD = (A) 12 (B) 13 (C) 15 (D) 17 (E) 24 \(AB = 8, BC = 6, AC = 10\) tell us that it is a right angle triangle. \(AC = \sqrt{15^2 + 8^2} = 17\) Another way (probably easier). Any side of the triangle cannot be more than that of the sum of the other two sides. Sum of the other two sides = 23 Hypotenuse is the largest side of a right angle triangle. We already have a base of 15. Only one option remains. Answer is D.
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Re: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD =
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12 Oct 2018, 06:54
Bunuel wrote: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD = (A) 12 (B) 13 (C) 15 (D) 17 (E) 24 Since triangle ABC is a 6810 triangle, it’s a right triangle with right angle at B. We can find AD, the hypotenuse of right triangle ABD, using the Pythagorean theorem, AB^2 + BD^2 = AD^2 8^2 + 15^2 = AD^2 64 + 225 = AD^2 289 = AD^2 17 = AD Answer: D
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Re: In the figure, if AB = 8, BC = 6, AC = 10 and CD = 9, then AD =
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