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07 Nov 2018, 02:06
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A
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In the figure shown below, the circle has center at the origin O, and point A has coordinates (13, 0). If point B is on the circle, what is the length of line segment AB?
(1) The X-coordinate of point B is −5.
(2) The Y-coordinate of point B is −12.
Attachment:
2018-11-07_1305.png
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07 Nov 2018, 06:04
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Bunuel
\(OA = 13\) & again \(OA^2 =13^2 +0^2 (x^2 +y^2 = a^2 , as centre at origin)\)
Also given B is on the circle \(x^2 +y^2 = a^2\)
1) for point B : \(x=-5\), thus we will get the value of \(y\) from \(x^2 +y^2 = a^2\) and also the value of \(AB\) from \(AB^2 = (13-x)^2 + (0-y)^2\) as we have both the value \(x\) & \(y\) ----- Sufficient.
2) for point B : \(y=-12\) , thus we will get the value of \(x\) from \(x^2 +y^2 = a^2\) and also the value of \(AB\) from \(AB^2 = (13-x)^2 + (0-y)^2\) as we have both the value \(x\) & \(y\) ----- Sufficient.
Ans D.
08 Nov 2018, 19:53
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From statemnt 1 there are two posible points for B: (-5,12) and (-5,-12). However both of them give the same line lenght. Hence sufficient.
From statemnt 2 there are two posible points for B: (-5,-12) and (5,-12). Each of them has different line lenghts. Hence insufficient.
Answer A
From statemnt 2 there are two posible points for B: (-5,-12) and (5,-12). Each of them has different line lenghts. Hence insufficient.
Answer A
