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In the first M games of a team's season, the ratio of the
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Updated on: 21 May 2013, 07:38
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In the first M games of a team's season, the ratio of the team's wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team's wins to its losses for all M+N games? A. 7:18 B. 9:23 C. 11:27 D. 23:54 E. 31:77
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Re: In the first M games of a team´s season, the ratio of the te
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21 May 2013, 07:19
josemarioamaya wrote: In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?
a) 7:18 b) 9:23 c) 11:27 d) 23:54 e) 37:77 The choice [E], I feel should be 31:77. **Request you to look into the source for the value. As for the solution, if M is the games played in the first half, Total wins = M/3 Total Losses = 2*M/3 Similarly for N games, with the ratio 1:3 Total wins = N/4 Total Losses = 3N/4 Hence when combined, total games become M+N Total wins = M/3 + N/4 Total losses = 2M/3 + 3N/4 Now with the above, we know M:N = 4:5 i.e. M = 4N/5. Substituting the values, Total wins = 31N/60 Total losses = 77N/60 Hence the ratio is 31:77. Please correct me if I am wrong! Regards, Arpan
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Re: In the first M games of a team´s season, the ratio of the te
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21 May 2013, 07:34
josemarioamaya wrote: In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?
a) 7:18 b) 9:23 c) 11:27 d) 23:54 e) 37:77 Are you sure that the option E is 37:77. I'm getting 31:77.



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Re: In the first M games of a team´s season, the ratio of the te
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21 May 2013, 07:46
I corrected the answer choice e it is 31:77



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Re: In the first M games of a team´s season, the ratio of the te
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21 May 2013, 11:08
josemarioamaya wrote: In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?
a) 7:18 b) 9:23 c) 11:27 d) 23:54 e) 31:77 As the final ratio is being asked, we can consider the value of M:N as 48:60. First M(48) games, Wins = 16;Losses = 32 Succesive N(60) games, Wins = 15;Losses = 45 Total Wins:Total Losses = (16+15)/(32+45) = 31/77 E.
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Re: In the first M games of a team´s season, the ratio of the te
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21 May 2013, 11:10
vinaymimani wrote: josemarioamaya wrote: In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?
a) 7:18 b) 9:23 c) 11:27 d) 23:54 e) 31:77 As the final ratio is being asked, we can consider the value of M:N as 48:60. First M(48) games, Wins = 16;Losses = 32 Succesive N(60) games, Wins = 15;Losses = 45 Total Wins:Total Losses = (16+15)/(32+45) = 31/77 E. Why cant we consider 12:15 and end up with the ratio 9:23 which is option (B)



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Re: In the first M games of a team´s season, the ratio of the te
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21 May 2013, 11:15
avinashrao9 wrote: vinaymimani wrote: josemarioamaya wrote: In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?
Why cant we consider 12:15 and end up with the ratio 9:23 which is option (B) You will never got 9:23 for 12:15 .You will still get 31:77.
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Re: In the first M games of a team´s season, the ratio of the te
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21 May 2013, 11:23
I considered the ratio wrong.. Though 12:15 satisfies 4:5 condition, it does not work out for the number of matches mentioned. It has to be 48:60.. Thanks



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Re: In the first M games of a team´s season, the ratio of the te
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17 May 2014, 07:31
How about 12:20, its a perfect fit for 4:5  M:N, an also all the other ratios.. and with this result I get 9:23.. really confused why this is the wrong answer.. Any help from the experts will be of great help! avinashrao9 wrote: I considered the ratio wrong.. Though 12:15 satisfies 4:5 condition, it does not work out for the number of matches mentioned. It has to be 48:60.. Thanks
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Re: In the first M games of a team´s season, the ratio of the te
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Re: In the first M games of a team´s season, the ratio of the te
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17 May 2014, 09:00
pkhats wrote: How about 12:20, its a perfect fit for 4:5  M:N, an also all the other ratios.. and with this result I get 9:23.. really confused why this is the wrong answer.. Any help from the experts will be of great help! avinashrao9 wrote: I considered the ratio wrong.. Though 12:15 satisfies 4:5 condition, it does not work out for the number of matches mentioned. It has to be 48:60.. Thanks 12:20 is 3:5 and not 4:5 as required. We know that the ratio of in first M games in 1:2 which means, we have denominator as 3 if we want to find the numbers of wins and losses. In second case, the ratio of next N games is 1:3, making denominator 4. Now M = 4x = 4 * 12x = 48 x (We are choosing 12 as it is LCM of 3 & 4) N = 5x = 5* 12x = 60 x Hence, we are taking the ratio as 48:60 and not any other ratio. Hope it helps!!!



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Re: In the first M games of a team´s season, the ratio of the te
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17 May 2014, 10:12
Oh! Thanks both, Silly me! These silly mistakes are gonna make me cry one day  Hope not! :p mittalg wrote: pkhats wrote: How about 12:20, its a perfect fit for 4:5  M:N, an also all the other ratios.. and with this result I get 9:23.. really confused why this is the wrong answer.. Any help from the experts will be of great help! avinashrao9 wrote: I considered the ratio wrong.. Though 12:15 satisfies 4:5 condition, it does not work out for the number of matches mentioned. It has to be 48:60.. Thanks 12:20 is 3:5 and not 4:5 as required. We know that the ratio of in first M games in 1:2 which means, we have denominator as 3 if we want to find the numbers of wins and losses. In second case, the ratio of next N games is 1:3, making denominator 4. Now M = 4x = 4 * 12x = 48 x (We are choosing 12 as it is LCM of 3 & 4) N = 5x = 5* 12x = 60 x Hence, we are taking the ratio as 48:60 and not any other ratio. Hope it helps!!!
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In the first M games of a team's season, the ratio of the
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18 Aug 2016, 17:14
M = 4/9 of total games N = 5/9 of total games
Wins out of M games = 1/3 Losses out of M games = 2/3
Wins out of N games = 1/4 Losses out of N games = 3/4
At this point, we should look at the denominators and come up with the least common multiple. LCM (9,3,4) = 108. This gives us the total number of games.
M = (4/9)*108 = 48 N = (5/9)*108 = 60
Wins out of M games = (1/3)*48 = 16 Losses out of M games = (2/3)*48 = 32
Wins out of N games = (1/4)*60 = 15 Losses out of N games = (3/4)*60 = 45
Total wins = 16 + 15 = 31 Total losses = 32 + 45 = 77
Desired ratio = 31/77
Answer (E).



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Re: In the first M games of a team's season, the ratio of the
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26 Jul 2018, 08:31
\(\frac{Total Wins}{Total Losses}\) = \(\frac{(16+15)}{(32+45)} = \frac{31}{77}\) Option E is the correct answer
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In the first M games of a team's season, the ratio of the
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26 Jul 2018, 10:39
josemarioamaya wrote: In the first M games of a team's season, the ratio of the team's wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team's wins to its losses for all M+N games?
A. 7:18 B. 9:23 C. 11:27 D. 23:54 E. 31:77 let M=3x let N=4y 3x/4y=4/5→ x/y=16/15 3*16=M=48 games: 16 wins; 32 losses 4*15=N=60 games: 15 wins; 45 losses (16+15)/(32+45)=31/77 E



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Re: In the first M games of a team's season, the ratio of the
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30 Jul 2018, 10:47
josemarioamaya wrote: In the first M games of a team's season, the ratio of the team's wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team's wins to its losses for all M+N games?
A. 7:18 B. 9:23 C. 11:27 D. 23:54 E. 31:77 Using the given ratio M:N of 4:5, we can let M = 4(12) = 48 and N = 5(12) = 60. So in the first 48 games, the team has ⅓(48) = 16 wins and ⅔(48) = 32 losses, and in the subsequent 60 games, the team has ¼(60) = 15 wins and ¾(60) = 45 losses. So the team’s winloss ratio is (16 + 15)/(32 + 45) = 31/77. Answer: E
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Re: In the first M games of a team's season, the ratio of the
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24 Jan 2019, 16:18
Understood the explanation using magic numbers, but here I am confused when I used balance method.
Look! for m games W/L= 1/2 for n games W/L= 1/3 for m+n games = W/L = x m:n= 4/5
from balance method (1/3 x)/(x1/2) = m:n = 4/5 here I got x= 11/27.
now please tell me where I am wrong.



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Re: In the first M games of a team's season, the ratio of the
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25 Jan 2019, 21:38
gvij2017 wrote: Understood the explanation using magic numbers, but here I am confused when I used balance method.
Look! for m games W/L= 1/2 for n games W/L= 1/3 for m+n games = W/L = x m:n= 4/5
from balance method (1/3 x)/(x1/2) = m:n = 4/5 here I got x= 11/27.
now please tell me where I am wrong. M/N = 4/5 Or we could say 48/60 In M matches(48) : 16 won and 32 lost In N matches (60): 15 won and 45 lost In M+N: (16+15)won and (32+45) lost which gives 31/77 hope it helps



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Re: In the first M games of a team's season, the ratio of the
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28 Jan 2019, 20:40
gvij2017 wrote: Understood the explanation using magic numbers, but here I am confused when I used balance method.
Look! for m games W/L= 1/2 for n games W/L= 1/3 for m+n games = W/L = x m:n= 4/5
from balance method (1/3 x)/(x1/2) = m:n = 4/5 here I got x= 11/27.
now please tell me where I am wrong. I have the same concern. Could any expert explain how to use the balance method here? Thank you.




Re: In the first M games of a team's season, the ratio of the
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