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In the given figure, the equation of line OB is y = 4x. Find the coordinates of B, if the coordinates of C is (5, 0).
(1) The slope of line BC is -\(\frac{1}{4[/fraction\)
(2) The lines OB and BC are perpendicular to each other.
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Responding to a PM...
If you look at the two statements, both give us the same information.. Slope of y=4x is 4 and the perpendicular line will have a slope of -\([fraction]1/4}\).
So both statements give us the slope to be -\(\frac{1}{4}\). Thus, the answer is either D or E.
Let us check the information given... I. The slope of BC is -\(\frac{1}{4}\) The equation of the line can be written as y=mx+c. Here m is the slope and equal to -\(\frac{1}{4}\).. So line with a point (5,0) with slope -\(\frac{1}{4}\) will be y=-\(\frac{1}{4}x+c\).....0=-\(\frac{1}{4}*5+c\).. Therefore c=\(\frac{4}{5}\).. The equation becomes y=-\(\frac{1}{4}x+5/4\).. B is common to the two lines, therefore the coordinates of B will be the solution of two equations. Substitute y=4x in above equation.. 4x=-\(\frac{1}{4}x+5/4\)... 16x=-1x+5.....x=5/17 and y=4*5/17=20/17 Sufficient Statement II.. The two lines are perpendicular Slope of y=4x is 4 as m is 4 here. Perpendicular line will have slope -1/m=-1/4.. Rest of the solution as above.. Sufficient
D
Hope it helps
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