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In the infinite sequence a_{1}, a_{2}, a_{3}, a_{n},....a_{n
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Updated on: 26 Jul 2013, 11:32
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In the infinite sequence \(a_{1}\), \(a_{2}\), \(a_{3}\), \(a_{n}\),....\(a_{n}\) = \(n^2\). What is \(a_{1323}a_{1322}\) ? (A) 2,245 (B) 2,645 (C) 5,290 (D) 5,545 (E) 5,790 Disclaimer: I have used the Search Box Before Posting. I used the first sentence of the question or a string of words exactly as they show up in the question below for my search. I did not receive an exact match for my question. Source: Veritas Prep; Book 04 Chapter: Homework Topic: Algebra Question: 90 Question: Page 223 Edition: Third My Question: Please provide an explanation on how to arrive at the answer.
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Originally posted by hb on 26 Jul 2013, 11:26.
Last edited by Bunuel on 26 Jul 2013, 11:32, edited 2 times in total.
Edited the question.




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Re: In the infinite sequence a_{1}, a_{2}, a_{3}, a_{n},....a_{n
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26 Jul 2013, 11:31
hb wrote: In the infinite sequence \(a_{1}\), \(a_{2}\), \(a_{3}\), \(a_{n}\),....\(a_{n}\) = \(n^2\). What is \(a_{1323}\)  \(a_{1322}\) ? (A) 2,245 (B) 2,645 (c) 5,290 (D) 5,545 (E) 5,790 Disclaimer: I have used the Search Box Before Posting. I used the first sentence of the question or a string of words exactly as they show up in the question below for my search. I did not receive an exact match for my question. Source: Veritas Prep; Book 04 Chapter: Homework Topic: Algebra Question: 90 Question: Page 223 Edition: Third My Question: Please provide an explanation on how to arrive at the answer. \(a_{1323} a_{1322}=1323^21322^2=(13231322)(1323+1322)=2645\) Answer: B.
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Re: In the infinite sequence a_{1}, a_{2}, a_{3}, a_{n},....a_{n
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02 Jan 2015, 03:03
look for pattern
a_2  a_1=41=3
a_3  a_2=94=5
a_4  a_3=169=7
a_5  a_4=2516=9
we see that every pair gives as a result the sum of terms, so solution is just
1323+1322=2645
B




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Re: In the infinite sequence a1, a2, a3, … an where an= n^2, what is a1,32
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10 Oct 2016, 21:08
an = n^2 From this a1323 = 1323*1323 and a1322 = 1322*1322 a1323 can be rewritten as 1323*(1322+1) = 1323*1322 + 1323 When subtracted with a1322, we get 1323 + 1322(13231322) = 1323 + 1322 = 2645 This solution is 2645(Option B)
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Re: In the infinite sequence a_{1}, a_{2}, a_{3}, a_{n},....a_{n
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10 Jan 2017, 00:51
[quote="hb"]In the infinite sequence \(a_{1}\), \(a_{2}\), \(a_{3}\), \(a_{n}\),....\(a_{n}\) = \(n^2\). What is \(a_{1323}a_{1322}\) ?
(A) 2,245 (B) 2,645 (C) 5,290 (D) 5,545 (E) 5,790
from stem
1323^2  1322^2 = ?? this is the difference of the squares of 2 successive integers ( thus (xy) in (x+y)(xy) = 1) thus the result is (x+y) ... add them together
gives B



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In the infinite sequence a_{1}, a_{2}, a_{3}, a_{n},....a_{n
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21 Jan 2017, 04:07
hb wrote: In the infinite sequence \(a_{1}\), \(a_{2}\), \(a_{3}\), \(a_{n}\),....\(a_{n}\) = \(n^2\). What is \(a_{1323}a_{1322}\) ? (A) 2,245 (B) 2,645 (C) 5,290 (D) 5,545 (E) 5,790 Disclaimer: I have used the Search Box Before Posting. I used the first sentence of the question or a string of words exactly as they show up in the question below for my search. I did not receive an exact match for my question. Source: Veritas Prep; Book 04 Chapter: Homework Topic: Algebra Question: 90 Question: Page 223 Edition: Third My Question: Please provide an explanation on how to arrive at the answer. \(a_n=n^2\) \(a_{1323}−a_{1322}=1323^2−1322^2=(1323−1322)(1323+1322)=2645\) Hence option B is correct.



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Re: In the infinite sequence a_{1}, a_{2}, a_{3}, a_{n},....a_{n
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16 Mar 2017, 14:19
Bunuel wrote: hb wrote: In the infinite sequence \(a_{1}\), \(a_{2}\), \(a_{3}\), \(a_{n}\),....\(a_{n}\) = \(n^2\). What is \(a_{1323}\)  \(a_{1322}\) ? (A) 2,245 (B) 2,645 (c) 5,290 (D) 5,545 (E) 5,790 Disclaimer: I have used the Search Box Before Posting. I used the first sentence of the question or a string of words exactly as they show up in the question below for my search. I did not receive an exact match for my question. Source: Veritas Prep; Book 04 Chapter: Homework Topic: Algebra Question: 90 Question: Page 223 Edition: Third My Question: Please provide an explanation on how to arrive at the answer. \(a_{1323} a_{1322}=1323^21322^2=(13231322)(1323+1322)=2645\) Answer: B. Nice way to subtract squares



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Re: In the infinite sequence a_{1}, a_{2}, a_{3}, a_{n},....a_{n
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17 Mar 2017, 01:20
a(1323)  a(1322) = 1323^2  1322^2 = (1323  1322)(1323+1322) = 1 * 2645 = 2645
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Re: In the infinite sequence a_{1}, a_{2}, a_{3}, a_{n},....a_{n
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21 Mar 2017, 05:19
hb wrote: In the infinite sequence \(a_{1}\), \(a_{2}\), \(a_{3}\), \(a_{n}\),....\(a_{n}\) = \(n^2\). What is \(a_{1323}a_{1322}\) ?
(A) 2,245 (B) 2,645 (C) 5,290 (D) 5,545 (E) 5,79 We are given that a(n) = n^2. So: a(1323)  a(1322) = 1323^2  1322^2 = (1323  1322)(1323 + 1322) = 1 x 2,645 = 2,645 Answer: B
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Re: In the infinite sequence a_{1}, a_{2}, a_{3}, a_{n},....a_{n
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20 Nov 2018, 07:42
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