subhashghosh wrote:
Hi Karishma
What is the meaning of this ?
"it means the part: (1+x(1+x(1+x(1+x)))) will get canceled from the num and den."
Regards,
Subhash
\(A2 = x + x^2 + x^3 + x^4 + x^5\)
\(\frac{An}{{x(1+x(1+x(1+x(1+x))))}} = x^5\)
Since the right side of the equation is just x^5, it means the entire expression: (1+x(1+x(1+x(1+x)))) should get canceled out which means we will get the same expression in the numerator as well. You don't need to do it. It is logical since otherwise, you will not get the reduced expression x^5. Also, you can see that you will get something like this in the numerator since the powers are increasing.
If you want to see it:
\(A2= x( 1 + x + x^2 + x^3 + x^4) = x( 1 + x(1 + x + x^2 + x^3)) = x( 1 + x(1 + x( 1 + x + x^2))) = x( 1 + x(1 + x( 1 + x( 1 + x))))\)
Similarly A7 \(= x^6( 1 + x(1 + x( 1 + x( 1 + x))))\)
So \(\frac{A7}{{x(1+x(1+x(1+x(1+x))))}} = \frac{x^6( 1 + x(1 + x( 1 + x( 1 + x))))}{x( 1 + x(1 + x( 1 + x( 1 + x))))}= x^5\)
Can you explain how to do this step: A2= x( 1 + x + x^2 + x^3 + x^4) = x( 1 + x(1 + x + x^2 + x^3)) = x( 1 + x(1 + x( 1 + x + x^2))) = x( 1 + x(1 + x( 1 + x( 1 + x))))