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# In the presidential election, 55% of the people who voted, voted for

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In the presidential election, 55% of the people who voted, voted for [#permalink]
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boomtangboy wrote:
In the presidential election, 55% of the people who voted, voted for the democratic candidate and 35% voted for the republican candidate. If 8% of the number of people eligible to vote, voted for neither the republican nor the democrat, what percent of people eligible to vote actually voted in the elections?

A.40
B.60
C.80
D.88
E.90

Hi,

I think this is the way how to solve this problem

Democractic : 55
Republican : 35
Total Eligible Population : x
Neither : 0.08x
(Its an election so you cant have both )

=> 55+35+0.08x = x
90 = 0.92 X
X = 100

Thus the percent of people eligible to vote actually voted in the elections = (55+35)/100 =>90/100 = 90%

Thus E

That's not correct.

If you are doing that way then you should have 55% + 35% + 0.08x% = 100%, because 55%, 35% and neither = 0.08x% together must sum up to 100% (all that voted). 55 + 35 + 0.08x = 100 --> x = 125 --> voted/eligible = 100/125 = 0.8.

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Re: In the presidential election, 55% of the people who voted, voted for [#permalink]
Smita04 wrote:
In the presidential election, 55% of the people who voted, voted for the democratic candidate and 35% voted for the republican candidate. If 8% of the number of people eligible to vote, voted for neither the republican nor the democrat, what percent of people eligible to vote actually voted in the elections?

A. 40
B. 60
C. 80
D. 88
E. 90

Let the Eligible number of voters = 100
Assume Actual number of people voted = x

55 + 35 = 90% of actual voters voted for either of the parties
—> 10% voted for neither
—> 10/100*x = 8 (Given)
—> x = 80

IMO Option C

Pls Hit kudos if you like the solution

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Re: In the presidential election, 55% of the people who voted, voted for [#permalink]
Smita04 wrote:
In the presidential election, 55% of the people who voted, voted for the democratic candidate and 35% voted for the republican candidate. If 8% of the number of people eligible to vote, voted for neither the republican nor the democrat, what percent of people eligible to vote actually voted in the elections?

A. 40
B. 60
C. 80
D. 88
E. 90

Given:
1. In the presidential election, 55% of the people who voted, voted for the democratic candidate and 35% voted for the republican candidate.
2. 8% of the number of people eligible to vote, voted for neither the republican nor the democrat,

Asked: What percent of people eligible to vote actually voted in the elections?

Let the number of people eligible to vote be x
Let the number of people actually voted be y

55%y + 35%y + 8%x = 100%y
8%x = 10%y
y/x = 8%/10% = 80%

The percent of people eligible to vote actually voted in the elections = 80%

IMO C
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Re: In the presidential election, 55% of the people who voted, voted for [#permalink]
Let total people eligible to vote= y
Total people voted= x
Democrats= 0.55 x
Republic= 0.35 x
Total= 0.9 X
Balance= 0.1 X..... These people didn't vote for both Democrats or Republicans

Now people who didn't vote for republic or Democrats are 0.08y.

So it means, 0.1 X = 0.08 Y hence X is 0.8 times Y which is 80% of Y.

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Re: In the presidential election, 55% of the people who voted, voted for [#permalink]
Total# ppl eligible to vote = T

# of ppl who actually voted = V

The percentage of ppl who actually voted who voted neither for Democrats nor for republicans = 100% - (55%) - (35%) = 10%

And this is ———-> 10%(V)

“8% of the ppl eligible to vote did so for neither”

10%(V) = 8%(T)

“What percent of eligible voters actually voted?”

Or

What’s is: (V / T) * (100)% = ?

10%(V) = 8%(T)

V/T = 8/10 = 80/100 ———-> 80%

(C) 80%

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Re: In the presidential election, 55% of the people who voted, voted for [#permalink]
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