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Updated on: 04 Jan 2023, 07:16
Originally posted by PawanRamnani1234 on 06 Sep 2016, 20:01.
Last edited by Bunuel on 04 Jan 2023, 07:16, edited 2 times in total.
Last edited by Bunuel on 04 Jan 2023, 07:16, edited 2 times in total.
Renamed the topic and edited the question.
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Difficulty:
45%
(medium)
Question Stats:
69% (02:10) correct
31%
(02:43)
wrong
based on 331
sessions
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In the rectangular coordinate system above, the area of parallelogram KLMN is :-
A. \(\frac{6}{\sqrt 3}\)
B. 6
C. \(6\sqrt3\)
D. 12
E. Cannot be determined.
Attachment:
2023-01-04_18-13-32.png [ 10.24 KiB | Viewed 2553 times ]
06 Sep 2016, 20:17
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Distance between K & L = 2 - 0 (x co-ordinates) = 2.
Since KL and MN are parallel, b is 3 (y o-ordinates on the same line).
Area = l * h = 2 * 3 = 6
Since KL and MN are parallel, b is 3 (y o-ordinates on the same line).
Area = l * h = 2 * 3 = 6
16 Oct 2016, 07:28
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If we try to solve this by equating the slopes for NK and ML, we get a as -2. -2 does not give a positive value for X coordinate for M (3a-2). Can someone please help resolve this?
Thank you.
Thank you.
