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In the rectangular coordinate system, if the line x = 2y + 5
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27 May 2012, 08:05
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In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ? A. 2 B. 0 C. 1/2 D. 1 E. 2
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Re: In the rectangular coordinate system, if the line x = 2y + 5
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27 May 2012, 08:19
macjas wrote: In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?
A. 2 B. 0 C. 1/2 D. 1 E. 2 The line x = 2y + 5 passes through points (m,n) and (m + 2,n + p) means that m=2n+5 and m+2=2(n+p)+5. Now, subtract the first equation from the second: (m+2)m=2(n+p)+5(2n+5) > 2=2p > p=1. Answer: D.
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Re: In the rectangular coordinate system, if the line x = 2y + 5
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29 May 2012, 06:46
Another way: Slope of the line can be calculated...
y=mx+c => y= (1/2)x5/2 => 1/2=n+pn/m+2m =>1/2=p/2 => p=1



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Re: In the rectangular coordinate system, if the line x = 2y + 5
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18 Mar 2015, 19:23
Hi All, When dealing with a graphing question, it often helps to convert any equations you've been given into "slopeintercept" format (and you might find it helpful to physically draw the graph so you can see it). Here, we're given the line X = 2Y = 5. Converting that into slopeintercept gives us: 2Y = X  5 Y = X/2  5/2 We're then told that the line passes through the points (M,N) and (M+2,N+P). We're asked for the value of P. Since we have the line, we can TEST a set of coordinate for (M,N) IF..... X = 0 Y = 5/2 So (M,N) is the point (0, 5/2) The second point is (M+2,N+P) Since our M = 0......M+2 = 2..... we have to see what happens when.... X = 2 Y = 1  5/2 = 3/2 So (M+2,N+P) is the point (2, 3/2) So between the first point and the second point, what has happened to the Y coordinate? It went from 5/2 to 3/2, so it INCREASED by 1. Thus, P = 1 Final Answer: GMAT assassins aren't born, they're made, Rich
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Re: In the rectangular coordinate system, if the line x = 2y + 5
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16 Jun 2015, 11:35
macjas wrote: In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?
A. 2 B. 0 C. 1/2 D. 1 E. 2 Rewrite x = 2y + 5 like so: y = 0.5X + 2.5 Plug in Values for m = x: if m = x = 1, the first point is 1, 3 if m = x = 3, the second point is 3, 4 Therefore n = 3 and n + p = 4. p = 1
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Re: In the rectangular coordinate system, if the line x = 2y + 5
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14 Jul 2016, 03:15
macjas wrote: In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?
A. 2 B. 0 C. 1/2 D. 1 E. 2 If 2y+5=x then, 2y=x5 or \(y=\frac{x}{2}\frac{5}{2}\) Now this has become the equation of line in the point slope form. {y=mx+b} slope (m) is 1/2 and we also know Slope (m)=\(\frac{y2y1}{x2x1}\) threfore putting the value of x and y from the question we get \(\frac{n+pn}{m+2m} = \frac{1}{2}\) \(\frac{p}{2}=\frac{1}{2}\) ===> p=1 ANSWER IS D
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Re: In the rectangular coordinate system, if the line x = 2y + 5
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04 Nov 2016, 05:17
EMPOWERgmatRichC wrote: Hi All, When dealing with a graphing question, it often helps to convert any equations you've been given into "slopeintercept" format (and you might find it helpful to physically draw the graph so you can see it). Here, we're given the line X = 2Y = 5. Converting that into slopeintercept gives us: 2Y = X  5 Y = X/2  5/2 We're then told that the line passes through the points (M,N) and (M+2,N+P). We're asked for the value of P. Since we have the line, we can TEST a set of coordinate for (M,N) IF..... X = 0 Y = 5/2 So (M,N) is the point (0, 5/2) The second point is (M+2,N+P) Since our M = 0......M+2 = 2..... we have to see what happens when.... X = 2 Y = 1  5/2 = 3/2 So (M+2,N+P) is the point (2, 3/2) So between the first point and the second point, what has happened to the Y coordinate? It went from 5/2 to 3/2, so it INCREASED by 1. Thus, P = 1 Final Answer: GMAT assassins aren't born, they're made, Rich I have been doing the EMPOWERgmat prep for the last month and I have already seen an improvement. You focus on very simple methods of breaking problems down. I'm not quite an assassin yet but I have to be soon. Thanks for the help. Posted from GMAT ToolKit



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In the rectangular coordinate system, if the line x = 2y + 5
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23 Jan 2017, 00:36
macjas wrote: In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?
A. 2 B. 0 C. 1/2 D. 1 E. 2 Since the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p) we have m=2n+5  I m+2=2(n+p)+5.  II solving I and II we have p =1 Hence option D is correct.



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Re: In the rectangular coordinate system, if the line x = 2y + 5
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25 Jan 2017, 10:19
macjas wrote: In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?
A. 2 B. 0 C. 1/2 D. 1 E. 2 We are given that line x = 2y + 5 passes through points (m,n) and (m + 2,n + p). Thus, we can make two equations and substitute m and m + 2 for x, and n and n + p for y. Equation 1: The ordered pair (m,n) means that x = m and y = n. Substitute these values into the equation x = 2y + 5. m = 2n + 5 Equation 2: The ordered pair (m + 2,n + p) means that we will let x = m + 2 and y = n + p. m + 2 = 2(n + p) + 5 m + 2 = 2n + 2p + 5 m = 2n + 2p + 3 We can equate equations 1 and 2 and we have: 2n + 5 = 2n + 2p + 3 5 = 2p + 3 2 = 2p p = 1 Alternate solution: We are given that line x = 2y + 5 passes through points (m,n) and (m + 2,n + p). We can find the slope of the line by isolating y: x = 2y + 5 2y = x  5 y = 1/2x  5/2 Thus, the line has slope 1/2. For any two points on this line, the slope between these two points must be 1/2 also. Since (m,n) and (m + 2,n + p) are on the line, the slope of the line connecting them must be 1/2. Therefore, using the slope formula, which is slope = (change in y)/(change in x), we have: (n + p  n)/(m + 2  m) = 1/2 p/2 = 1/2 p = 1 Answer: D
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Re: In the rectangular coordinate system, if the line x = 2y + 5
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21 Jul 2018, 00:24
Bunuel wrote: macjas wrote: In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?
A. 2 B. 0 C. 1/2 D. 1 E. 2 The line x = 2y + 5 passes through points (m,n) and (m + 2,n + p) means that m=2n+5 and m+2=2(n+p)+5. Now, subtract the first equation from the second: (m+2)m=2(n+p)+5(2n+5) > 2=2p > p=1. Answer: D. Hi pushpitkc how is your gmat prep ? hope bumpy roads, pit stops are already behind you, and there is just highway in front of you can you break down Bubuel`s solution please i dont understand how from here x = 2y + 5 passes through points (m,n) and (m + 2,n + p) he concludes that that m=2n+5 and m+2=2(n+p)+5. i can replace (m,n) and (m + 2,n + p) with x, y, p for example (x,y) and (x + 2, y + p) have a great weekend




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