altairahmad wrote:
Bunuel VeritasKarishma chetan2uHad the question restricted the solution to integers, then the only solution would be 1,1,2,3,5,8,13,21.... right ?
Thanks
You are right. The integers still has to be the same, but we can add some fractions ("numbers") in the beginning of the sequence to prolong the sequence. Like this:
21-13-8-5-3-2-1-1-0,6-0,4-0,2-0,2-0
In this case 0,6 is the fifth term.
However, you can not change the integers. Then the sequence will die before making it to the 5th term. For example: 21-13,5-7,5-6-1,5... or 21-12,5-8,5-4...
Any objections to this?
Edit: But wait, of course I can not prolong the Fibonacci like that. It gets killed on the 1-1-part. Hmm. Are there actually any other solutions to this problem than the 5th term being 5, from what we get in statement 2? Please post another solution.
Edit 2: From what I can see we can only change the sequence by adding 0 or not in the beginning of the sequence. Adding 0 though changes the fact that the 8th term has to be 21.
21-13-8-5-3-2-1-1
or
21-13-8-5-3-2-1-1-0
Now the 8th term is 13.
I believe there is no other solution to statement 2 than t5 being 5. Anyone has another solution, or the correct answer must be D.