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In the table above, if no one is assigned to more than one project, wh

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Re: In the table above, if no one is assigned to more than one project, wh [#permalink]
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Bunuel wrote:

In the table above, if no one is assigned to more than one project, what is the number of women assigned to Project 2?

A. 100
B. 75
C. 50
D. 25
E. 15

Attachment:
image666.jpg

We can create the equations:

a + b = 200

and

a + c = 180

and

b + c = 70

If we subtract the second equation from the first, we have:

b - c = 20

If we add the above equation and the third equation, we have:

2b = 90

b = 45

Thus, c = 25.

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Re: In the table above, if no one is assigned to more than one project, wh [#permalink]
Another way to look at this problem is as follows.

Option A and B can easily be eliminated because they won't satisfy equation for people in group 3.

Then we can use hit a trial. I started off with 25.
If C = 25, then B = 45 (Eq 3)
If B = 45, then A = 155 (Eq 1)
If A = 155, then C = 25 (Eq 2)

This confirms that C = 25.

Hence, D.
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Re: In the table above, if no one is assigned to more than one project, wh [#permalink]
1
Kudos
Bunuel wrote:

In the table above, if no one is assigned to more than one project, what is the number of women assigned to Project 2?

A. 100
B. 75
C. 50
D. 25
E. 15

Attachment:
image666.jpg

a+b = 200
a+c = 180
b+c = 70

a+b+c = 225
c = (a+b+c) - (a+b) = 225 - 200 = 25

IMO D
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Re: In the table above, if no one is assigned to more than one project, wh [#permalink]
Bunuel wrote:

In the table above, if no one is assigned to more than one project, what is the number of women assigned to Project 2?

A. 100
B. 75
C. 50
D. 25
E. 15

Attachment:
image666.jpg

Video Explanation

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Re: In the table above, if no one is assigned to more than one project, wh [#permalink]
1
Kudos
Bunuel wrote:

In the table above, if no one is assigned to more than one project, what is the number of women assigned to Project 2?

A. 100
B. 75
C. 50
D. 25
E. 15

Attachment:
image666.jpg

a + b = 200 (1)
a + c = 180 (2)
b + c = 70 (3)

2a + 2b + 2c = 450
a + b + c = 225 (4)

(4) - (1)
c = 25

IMO D
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Re: In the table above, if no one is assigned to more than one project, wh [#permalink]
This is how I approached.

a+b=200 - (1)

a+c=180 - (2)

Substract (1) by (2)

then b-c = 20 - (4)

b+c= 70 - (3)

then 2b = 90, b = 45

then c = 25
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Re: In the table above, if no one is assigned to more than one project, wh [#permalink]
1
Kudos
a + b = 200 -----(1)
a + c = 180 -----(2)

(1) - (2) => b - c = 20 -----(3)

=> b + c = 70 -----(4)

(3) + (4) => 2b = 90

=> b = 45.

=> 45 + c = 70

=> c = 25

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Re: In the table above, if no one is assigned to more than one project, wh [#permalink]
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Re: In the table above, if no one is assigned to more than one project, wh [#permalink]
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