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# In the x-y plane, what is the slope between y-intercept and a negativ

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Math Revolution GMAT Instructor
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In the x-y plane, what is the slope between y-intercept and a negativ [#permalink]

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09 Mar 2017, 01:42
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53% (01:12) correct 47% (01:38) wrong based on 77 sessions

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In the x-y plane, what is the slope between y-intercept and a negative x-intercept of $$y=x^2+x-6$$?

A. -2
B. -3
C. 2
D. 4
E. 6
[Reveal] Spoiler: OA

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Last edited by MathRevolution on 12 Mar 2017, 17:46, edited 1 time in total.
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Re: In the x-y plane, what is the slope between y-intercept and a negativ [#permalink]

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09 Mar 2017, 02:40
y = x^2 +x -6
for y intercept, x = 0. Putting the value we get y=-6. hence the co-ordinate = (0,-6)
For the x-intercept, y=0. Putting the value ,we get x^2 +x-6 = 0 or x = -3 or 2.
Since the negative x-intercept is required, coordinate will be (-3,0)

Slope of the line passing through (-3,0) and (0,-6) = (0 +6)/(-3-0) = -2

Option A
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Re: In the x-y plane, what is the slope between y-intercept and a negativ [#permalink]

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12 Mar 2017, 17:46
==> From y=x2+x-6=(x+3)(x-2)=0, the x-intercept becomes (-3,0) or (2,0), and (0,-6). From these, the negative x-intercept is (-3,0) and the negative y-intercept is (0,-6). The slope of the straight line that passes through the two points becomes $$\frac{0-(-6)}{-3-0=-2}$$

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Re: In the x-y plane, what is the slope between y-intercept and a negativ [#permalink]

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13 Mar 2017, 00:06
For y intercept x is 0 so we get y=-6 i.e (0,-6)
For the x-intercept, y=0. Putting the value ,we get x^2 +x-6 = 0 or x = -3 or 2.
question is stating about negative x-intercept so we choose (-3,0)

Slope of the line passing through (-3,0) and (0,-6) = (0 +6)/(-3-0) = -2
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Re: In the x-y plane, what is the slope between y-intercept and a negativ [#permalink]

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13 Mar 2017, 11:35
"What is the slope between point A and B.........."
Hum... this does not sound clear to me.

Why not saying "What is the slope of the line passing through point A and B?"
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Re: In the x-y plane, what is the slope between y-intercept and a negativ   [#permalink] 13 Mar 2017, 11:35
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