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555-605 Level|   Coordinate Geometry|                              
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lakshya14
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In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three ve 04 Jan 2021, 08:29
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VeritasKarishma
Baten80
In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three vertices of a certain square. If c < 0 and d > 0, which of the following points is in the same quadrant as the fourth vertex of the square?

A. (-5, -3)
B. (-5, 3)
C. (5, -3)
D. (3, -5)
E. (3, 5)

I answered B. But OA

Your logic was fine.. You figured that after (c, d), (c, -d), and (-c, -d), the fourth vertex would be (-c, d). Perfect!
The only problem was the additional info that said that 'c' is negative and 'd' is positive. This means that in (-c, d), both (-c) and d will be positive! Hence the OA is (E) i.e. the one in which both, the x and the y co-ordinate, are positive.
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How do we know specifically the "fourth vertex"? Is it the fourth quadrant point or the missing one?
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woohoo921
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In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three ve 13 Dec 2022, 19:38
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KarishmaB
Baten80
In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three vertices of a certain square. If c < 0 and d > 0, which of the following points is in the same quadrant as the fourth vertex of the square?

A. (-5, -3)
B. (-5, 3)
C. (5, -3)
D. (3, -5)
E. (3, 5)

I answered B. But OA

Your logic was fine.. You figured that after (c, d), (c, -d), and (-c, -d), the fourth vertex would be (-c, d). Perfect!
The only problem was the additional info that said that 'c' is negative and 'd' is positive. This means that in (-c, d), both (-c) and d will be positive! Hence the OA is (E) i.e. the one in which both, the x and the y co-ordinate, are positive.
Show more

KarishmaB
Thank you for this helpful reply. I realize that the answer needed to be (positive #, positive #), but I was confused on expressing c given that c is less than 0 converting the variable into an actual number. I thought that I needed to reverse the variable to be positive so in other words, I chose B. I would be so appreciative for your view as to why you don't have to do this. Thank you again.
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KarishmaB
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In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three ve 13 Dec 2022, 20:37
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woohoo921
KarishmaB
Baten80
In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three vertices of a certain square. If c < 0 and d > 0, which of the following points is in the same quadrant as the fourth vertex of the square?

A. (-5, -3)
B. (-5, 3)
C. (5, -3)
D. (3, -5)
E. (3, 5)

I answered B. But OA

Your logic was fine.. You figured that after (c, d), (c, -d), and (-c, -d), the fourth vertex would be (-c, d). Perfect!
The only problem was the additional info that said that 'c' is negative and 'd' is positive. This means that in (-c, d), both (-c) and d will be positive! Hence the OA is (E) i.e. the one in which both, the x and the y co-ordinate, are positive.

KarishmaB
Thank you for this helpful reply. I realize that the answer needed to be (positive #, positive #), but I was confused on expressing c given that c is less than 0 converting the variable into an actual number. I thought that I needed to reverse the variable to be positive so in other words, I chose B. I would be so appreciative for your view as to why you don't have to do this. Thank you again.
Show more

Take an example in such cases. You know that the fourth vertex would be (-c, d).
Now since c is negative, c can be say -1 and since d is positive, d can be 1. So the vertex becomes (-(-1), 1) i.e. (1, 1).
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In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three ve 20 Dec 2024, 03:25
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Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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