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In triangle ABC, find z if AB = 5 and y = 40.

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In triangle ABC, find z if AB = 5 and y = 40. [#permalink]

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New post 24 Oct 2017, 23:50
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A
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C
D
E

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  45% (medium)

Question Stats:

65% (00:52) correct 35% (00:50) wrong based on 49 sessions

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In triangle ABC, find z if AB = 5 and y = 40.

(1) BC = 5
(2) The bisector of angle B is perpendicular to AC.

[Reveal] Spoiler:
Attachment:
2017-10-25_1048.png
2017-10-25_1048.png [ 5.96 KiB | Viewed 414 times ]
[Reveal] Spoiler: OA

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In triangle ABC, find z if AB = 5 and y = 40. [#permalink]

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New post 24 Oct 2017, 23:54
Option D

From st1 we can conclude that this is an isosceles triangle. Hence x=40. Hence z=100. Hence sufficient
From st2 we can draw a perpendicular line from B. From this new triangle we can find that half angle of z=50. Hence z=100. Hence sufficient

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In triangle ABC, find z if AB = 5 and y = 40. [#permalink]

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New post 31 Oct 2017, 11:49
Bunuel wrote:
Image
In triangle ABC, find z if AB = 5 and y = 40.

(1) BC = 5
(2) The bisector of angle B is perpendicular to AC.

[Reveal] Spoiler:
Attachment:
2017-10-25_1048.png


I went with D, both are sufficient.

St 1, gives us an isosceles triangle. Therefore, angle x and y both = 40, therefore z = 100.
St 2, if a bisector of an angle is perpendicular than it's isosceles, so angles x and y both equal 40.

Also, it appears I got this right, but the wrong way.
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I'd love to hear any feedback or ways to improve my problem solving. I make a lot of silly mistakes. If you've had luck improving on stupid mistakes, I'd love to hear how you did it.

Also, I appreciate any kudos.

Kudos [?]: 8 [0], given: 18

In triangle ABC, find z if AB = 5 and y = 40.   [#permalink] 31 Oct 2017, 11:49
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In triangle ABC, find z if AB = 5 and y = 40.

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