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Sherel
Joined: 29 Jun 2019
Last visit: 16 Apr 2022
Posts: 7
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Given Kudos: 2
Location: India
Schools: Kelley '22 (A$$$$$)
GMAT 1: 730 Q48 V41
11 Jul 2019, 21:21
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An architect is planning to incorporate several stone spheres of different font-sizes into the landscaping of a public park, and workers who will be applying a finish to the exterior of the spheres need to know the surface area of each sphere. The finishing process costs $92 per square meter. The surface area of a sphere is equal to 4\pir 2, where r is the radius of the sphere.
In the table, select the value that is closest to the cost of finishing a sphere with a 5.50-meter circumference as well as the cost of finishing a sphere with a 7.85-meter circumference. Make only two selections, one in each column.
Finishing cost
0, $900
$1,200
$1,800
$2,800
$3,200
$4,500
Given answer is: 5.50m - $900, 7.85m - $1800
In the table, select the value that is closest to the cost of finishing a sphere with a 5.50-meter circumference as well as the cost of finishing a sphere with a 7.85-meter circumference. Make only two selections, one in each column.
Finishing cost
0, $900
$1,200
$1,800
$2,800
$3,200
$4,500
Given answer is: 5.50m - $900, 7.85m - $1800
12 Jul 2019, 00:00
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Cost ......... Simply it's costly
12 Jul 2019, 07:55
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\(2(pi)r = 5.5\)
So calculate r.
Using this find the surface area in \(4(pi)r^2\)
Multiple this surface area by the cost per m^2
So calculate r.
Using this find the surface area in \(4(pi)r^2\)
Multiple this surface area by the cost per m^2
