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Bunuel
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Bunuel
Is \(3^x < x^3\)?


(1) \(3^x > 1\)

(2) \(0 < x < 1\)

what should be ideal approach for this question plugin or concept??
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Bunuel
Is \(3^x < x^3\)?


(1) \(3^x > 1\)

(2) \(0 < x < 1\)

what should be ideal approach for this question plugin or concept??

Hi dhruv solanki

Any approach that helps you solve the question within 2 minutes and strike you first should be the ideal approach.
The so called short-cut methods you might have come across will rarely give you confidence under GMAT exam pressure and chances are you might miss a hidden concept required to solve the question.

Anyways so far I have not come across a real GMAT question that cannot be solved within 2 minutes using proper mathematical concept :grin: :grin:
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Bunuel
Is \(3^x < x^3\)?


(1) \(3^x > 1\)

(2) \(0 < x < 1\)

what should be ideal approach for this question plugin or concept??


Hi..

you will agree any question done on concept is surely correct and increases your confidence level..
as here if you know -
x is negative :- 3^x will be <1... it in all probability will be a positive fraction AND x^3 will be negative
x is 0 :- 3^x will be 1 AND x^3 will be 0
and so x>0 will give you a value more than 3^0 or 1 AND x^3 is less than 1 if 0<x <1

so when you know these, you will be sure of answer..

OR you will have to plug three values - highest possible, lowest possible and something in middle and still can be in some doubt.
ofcourse if you do not know concept, go for substitution

substitution on the other hand is very effective in few cases
when you are asked for value of x in some equation and choices are given
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Bunuel
Is \(3^x < x^3\)?


(1) \(3^x > 1\)

(2) \(0 < x < 1\)

what should be ideal approach for this question plugin or concept??


Hi..

you will agree any question done on concept is surely correct and increases your confidence level..
as here if you know -
x is negative :- 3^x will be <1... it in all probability will be a positive fraction AND x^3 will be negative
x is 0 :- 3^x will be 1 AND x^3 will be 0
and so x>0 will give you a value more than 3^0 or 1 AND x^3 is less than 1 if 0<x <1

so when you know these, you will be sure of answer..

OR you will have to plug three values - highest possible, lowest possible and something in middle and still can be in some doubt.
ofcourse if you do not know concept, go for substitution

substitution on the other hand is very effective in few cases
when you are asked for value of x in some equation and choices are given


in this question, suppose x=3 then it will be equal so is the information insufficient?
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dhruv solanki
Bunuel
Is \(3^x < x^3\)?


(1) \(3^x > 1\)

(2) \(0 < x < 1\)

in this question, suppose x=3 then it will be equal so is the information insufficient?

Hi..

If one of the statement said that x=3..
so our answer for "Is \(3^x<x^3\) ?" will be NO and the statement will be sufficient as it is giving us a clear NO
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pushpitkc
(1) \(3^x > 1\)
If x=1 or 3, the equation \(3^x < x^3\) is not true
But, if x = \(\frac{5}{2}\), the equation \(3^x < x^3\) is true.(Insufficient)

(2) \(0 < x < 1\)
If value of x is between 0 and 1,
x could be \(\frac{1}{4}\) or \(\frac{1}{2}\)
When we plug x=\(\frac{1}{2}\), \(3^x < x^3\) is false
Similarly when we plug x=\(\frac{1}{4}\) also, \(3^x < x^3\) is false.
Whatever the value of x in this range, the equation is always false(Sufficient) (Option B)

1) How did you think of 5/2 in this case?
2) Even if you did, calculating the values is so tough without a calculator. The first term is 15.58, while the second one is 15.62. Little too tough don't you think?
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Hi chetan2u and other members, can anybody help me in breaking the 1st statement? How do you solve 3^x>x^3?
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Bunuel
Is \(3^x < x^3\)?


(1) \(3^x > 1\)

(2) \(0 < x < 1\)

Hi Brian123

The question requires to be looked at from perspective of what the GMAT can test you at max.

You won’t require to solve the inequality completely, but analyse it from the perspective of GMAT.

Let us analyse \(3^x<x^3\).

1) When x is negative
\(3^x\) may be a fraction but always >0
\(x^3\) <0.
So answer will be NO
2) When x is a positive fraction <1
\(3^x\) will be greater than 1 even if x is 0.0000001, because even 3^0=1
\(x^3<x<1\)
So answer will again be NO
3) x>1
Now there can be certain situations where we will get yes and somewhere no.
Both 3^x and x^3 are different curves which surely intersect at x=3.
If they intersect at 3, surely somewhere x^3>3^x
Just for information, 2.5<x<3, the answer will be YES. In all other values of x, the answer is NO.

answer is yes if 2.5<x<3, otherwise no.

\(1. \ \ 3^x>1\)
We know this is true for all positive values of x, that is x>0.
Case (3) gives both yes and no.
Insufficient

\(2. \ \ 0<x<1\)
Case (2) , so answer is always NO
Sufficient


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