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Is 4^(x+y)=8^(10) ?
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18 Sep 2012, 03:19
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Is \(4^{x+y}=8^{10}\) ? (1) x  y = 9 (2) y/x = 1/4 Practice Questions Question: 41 Page: 278 Difficulty: 600
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Re: Is 4^(x+y)=8^(10) ?
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18 Sep 2012, 03:20
SOLUTIONIs \(4^{x+y}=8^{10}\) ?Work with the same base: is \(4^{x+y}=8^{10}\) ? > is \(2^{2(x+y)}=2^{30}\) ? > is \(2(x+y)=30\)? is \(x+y=15\)? (1) x  y = 9. Not sufficient. (2) y/x = 1/4 > \(x=4y\). Not sufficient. (1)+(2) We have two distinct linear equation with two unknowns (\(x  y = 9\) and \(x=4y\)), hence we can solve for both of them and get whether \(x+y=15\) is true. Sufficient. Answer: C.
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Re: Is 4^(x+y)=8^(10) ?
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18 Sep 2012, 05:20
Is 4^{x+y}=8^{10} ? (1) x  y = 9 (2) y/x = 1/4 \(4^{x+y}=8^{10}\) > \(2^2{x+y}=2^3{10}\)>\(2^{x+y}=2^{15}\) The question can be restated as Is x+y = 15? 1) xy = 9 >Since x & y can assume any value>Insufficient 2) x= 4y > No Absolute value is given for x & y, Only ratio is given> Insufficient 1+2) 4yy = 9 > 3y=9>Sufficient Thus Answer C
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Re: Is 4^(x+y)=8^(10) ?
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18 Sep 2012, 06:49
Bunuel wrote: Is \(4^{x+y}=8^{10}\) ?
(1) x  y = 9 (2) y/x = 1/4
the given eqn can be solved as: 2^2(x+y) = 2^3(10) => x+y = 15 Stmt 1) x  y = 9 can take many values for x and y and satisfy the eqn Stmt 2) y/x = 1/4, here also x and y can take many values combining both 1) and 2) the eqn can be solved to get values of x and y and can be verified if these x and y satisfies the given eqn Hence C
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Re: Is 4^(x+y)=8^(10) ?
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18 Sep 2012, 10:13
Bunuel wrote: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectIs \(4^{x+y}=8^{10}\) ? (1) x  y = 9 (2) y/x = 1/4 Practice Questions Question: 41 Page: 278 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you! From the question is X + Y = 15? 1st Option X  Y = 9 it can be any thing and any no. not necessarly the nos whose sum is equal to 15. Not Sufficient. 2nd Option: Y/x = 1/4 again Y and X can be any thing not necessarly the nos. whose summ is equal to 15. Not sufficient. Combining Both options: X  X/4 = 9 X = 12 therefore Y = 3. so Answer is "C". If my explaination you like kindly give one KUDOS



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Re: Is 4^(x+y)=8^(10) ?
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20 Sep 2012, 00:39
The question is simply is x + y = 15? All we need is to know the value of the sum of x and y to get sufficiency. (1) x y= 9 10  1 is 9 11  2 is 9 24  9 is 15 INSUFFICIENT (2) y/x = 1/4 or 4y = x many possibilities , INSUFFICENT X  y = 9 (4y)  Y = 9 y = 3 x = 12 answer: c
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Re: Is 4^(x+y)=8^(10) ?
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21 Sep 2012, 03:57
Ans:C 4^(x+y)=8^(10) =>2^2(x+y)=2^3(10) =>x+y=15? Statement1:xy=9Insufficent Statement2:y/x=1/4=>x=4yInsufficent By combining St1&st2 y=3 and x=12 which gives x+y=15Sufficient



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Re: Is 4^(x+y)=8^(10) ?
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03 Mar 2013, 22:21
Hi, could you please help clarify? I'm a little bit confused.
Isn't the answer D?
(1) XY=9 > X=9+Y We can just put "X=Y+9" in the initial equation X+Y=15 to solve the equation without any help from the 2nd equation, y/x = 1/4.
The same goes to the second equation (2) y/x = 1/4 > X=4Y Just put substitute the X in the initial equation, X+Y=15, with the 4Y and then solve the equation for both X and Y.
So, we can actually get the answer using only 1 of statement. So why is the answer C.
Billion thanks in advance!



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Re: Is 4^(x+y)=8^(10) ?
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04 Mar 2013, 03:27
wutthiyo wrote: Hi, could you please help clarify? I'm a little bit confused.
Isn't the answer D?
(1) XY=9 > X=9+Y We can just put "X=Y+9" in the initial equation X+Y=15 to solve the equation without any help from the 2nd equation, y/x = 1/4.
The same goes to the second equation (2) y/x = 1/4 > X=4Y Just put substitute the X in the initial equation, X+Y=15, with the 4Y and then solve the equation for both X and Y.
So, we can actually get the answer using only 1 of statement. So why is the answer C.
Billion thanks in advance! Welcome to GMAT Club! Actually the correct answer is C, not D. From the stem the question became: is x + y = 15? Now, (2) says that x  y = 9. Can we tell from this whether x + y = 15? No! Consider x = 10 and y = 1 for a NO answer and x = 12 and y = 3 for an YES answer. Hence, the first statement is NOT sufficient. The same for the second statement. The problem with your solution is that you assumed that we have two equations for each statement, whereas we have just one: x  y = 9 for (1) and y/x = 1/4 for (2). The second equation, x + y = 15 is not given to be true, we are asked to find whether it's true. Hope it's clear.
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Re: Is 4^(x+y)=8^(10) ?
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05 Mar 2013, 23:50
Bunuel wrote: Welcome to GMAT Club!
Actually the correct answer is C, not D.
From the stem the question became: is x + y = 15?
Now, (2) says that x  y = 9. Can we tell from this whether x + y = 15? No! Consider x = 10 and y = 1 for a NO answer and x = 12 and y = 3 for an YES answer. Hence, the first statement is NOT sufficient.
The same for the second statement.
The problem with your solution is that you assumed that we have two equations for each statement, whereas we have just one: x  y = 9 for (1) and y/x = 1/4 for (2). The second equation, x + y = 15 is not given to be true, we are asked to find whether it's true.
Hope it's clear.
Oh! Thanks a lot! That's clear. So when a question ask whether an equation is true or not, we cannot use it in solving the problem. Am I right? ^___^



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Re: Is 4^(x+y)=8^(10) ?
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06 Mar 2013, 02:35
wutthiyo wrote: Bunuel wrote: Welcome to GMAT Club!
Actually the correct answer is C, not D.
From the stem the question became: is x + y = 15?
Now, (2) says that x  y = 9. Can we tell from this whether x + y = 15? No! Consider x = 10 and y = 1 for a NO answer and x = 12 and y = 3 for an YES answer. Hence, the first statement is NOT sufficient.
The same for the second statement.
The problem with your solution is that you assumed that we have two equations for each statement, whereas we have just one: x  y = 9 for (1) and y/x = 1/4 for (2). The second equation, x + y = 15 is not given to be true, we are asked to find whether it's true.
Hope it's clear.
Oh! Thanks a lot! That's clear. So when a question ask whether an equation is true or not, we cannot use it in solving the problem. Am I right? ^___^ Yes, you cannot use it as a given.
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Re: Is 4^(x+y)=8^(10) ?
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07 Jun 2013, 05:13
Hey guys,
Why do you have to reduce the base to 2? Why cant we just change the base of 8 to 4 so thats it reads X+y=20? That would seem to be easier but mathematically Im not coming out to the correct answer. Can someone help?



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Re: Is 4^(x+y)=8^(10) ?
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07 Jun 2013, 05:32
AlphaMan21 wrote: Hey guys,
Why do you have to reduce the base to 2? Why cant we just change the base of 8 to 4 so thats it reads X+y=20? That would seem to be easier but mathematically Im not coming out to the correct answer. Can someone help? \(8^{10}\) cannot be written as \(4^{20}\), \(4^{20}=4^{2*10}=16^{10}\neq{8^{10}}\). Hope it's clear
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Re: Is 4^(x+y)=8^(10) ?
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27 Oct 2013, 08:20
Bunuel wrote: SOLUTION
Is \(4^{x+y}=8^{10}\) ?
Work with the same base: is \(4^{x+y}=8^{10}\) ? > is \(2^{2(x+y)}=2^{30}\) ? > is \(2(x+y)=30\)? is \(x+y=15\)?
(1) x  y = 9. Not sufficient. (2) y/x = 1/4 > \(x=4y\). Not sufficient.
(1)+(2) We have two distinct linear equation with two unknowns (\(x  y = 9\) and \(x=4y\)), hence we can solve for both of them and get whether \(x+y=15\) is true. Sufficient.
Answer: C. Here's the approach I did, it took me roughly 5 minutes to complete, would you be able to tell me how to get faster, and if i plugged Y into the correct question. From the Q.Stem I simplified the Question down to, does "x+y=15" Yes/No. Statement 1) xy=9 x+y=9+y X=9+Y I used substation, plugged in X with the original equation, and I got 9+2y=15, reduced down to y=3. So the question is reduced to "does Y=3, yes or no" from what I know, I'm Not sure. So therefore it's not sufficient. Statement 2) y/x=1/4 is simplified to 4Y=X, I Plugged in to the original equation X+Y=15 So now I have 4Y+Y=15 5Y=15, The question is now rephrased as does y equal 3? again, it's not sufficient. (C) X+Y=15 From Statement 1 & Statement 2, Y=3, I plugged in the following X+Y=15 X3=3 X=12 Banuel, If I went wrong anywhere, can you tell me where I went wrong. Should I test the answer choice to see if it's insufficient, instead of labeling the answer not sufficient? For statement one, I found myself answering, yes it's sufficient to solve, but X is not given, so I should not assume that the number is automatically "x=12" correct? The simplification is reducing the question still" Does Y=3? and that changes it all, because I don't know if Y=3. So is that enough information to move on? Same reasoning on the second statement. Threw me off for a bit.



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Re: Is 4^(x+y)=8^(10) ?
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28 Oct 2013, 00:35
selfishmofo wrote: Bunuel wrote: SOLUTION
Is \(4^{x+y}=8^{10}\) ?
Work with the same base: is \(4^{x+y}=8^{10}\) ? > is \(2^{2(x+y)}=2^{30}\) ? > is \(2(x+y)=30\)? is \(x+y=15\)?
(1) x  y = 9. Not sufficient. (2) y/x = 1/4 > \(x=4y\). Not sufficient.
(1)+(2) We have two distinct linear equation with two unknowns (\(x  y = 9\) and \(x=4y\)), hence we can solve for both of them and get whether \(x+y=15\) is true. Sufficient.
Answer: C. Here's the approach I did, it took me roughly 5 minutes to complete, would you be able to tell me how to get faster, and if i plugged Y into the correct question. From the Q.Stem I simplified the Question down to, does "x+y=15" Yes/No. Statement 1) xy=9 x+y=9+y X=9+Y I used substation, plugged in X with the original equation, and I got 9+2y=15, reduced down to y=3. So the question is reduced to "does Y=3, yes or no" from what I know, I'm Not sure. So therefore it's not sufficient. Statement 2) y/x=1/4 is simplified to 4Y=X, I Plugged in to the original equation X+Y=15 So now I have 4Y+Y=15 5Y=15, The question is now rephrased as does y equal 3? again, it's not sufficient. (C) X+Y=15 From Statement 1 & Statement 2, Y=3, I plugged in the following X+Y=15 X3=3 X=12 Banuel, If I went wrong anywhere, can you tell me where I went wrong. Should I test the answer choice to see if it's insufficient, instead of labeling the answer not sufficient? For statement one, I found myself answering, yes it's sufficient to solve, but X is not given, so I should not assume that the number is automatically "x=12" correct? The simplification is reducing the question still" Does Y=3? and that changes it all, because I don't know if Y=3. So is that enough information to move on? Same reasoning on the second statement. Threw me off for a bit. 5 minutes is too much for this problem. The question boils down to whether \(x+y=15\). (1) says x  y = 9. Can we answer whether \(x+y=15\)? No, because infinitely many pairs of (x, y) satisfy x  y = 9, and only one of them yields the sum of 15, namely x=12 and y=3. (2) says x=4y. Basically the same here: can we answer whether \(x+y=15\)? No, because infinitely many pairs of (x, y) satisfy x=4y, and only one of them yields the sum of 15. When we combine the statements we have xy=9 and x=4y. So, we have two two distinct linear equation with two unknowns, hence we can solve for both of them and get whether \(x+y=15\) is true. As you can see we don't need to solve anything for this question to get the answer. Hope it helps.
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Is 4^(x+y)=8^(10) ?
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20 Nov 2014, 10:58
Hi, could someone please help me evaluate my approach? I got stuck...
I did it this way:
\(4^x^+^y = 8^1^0 > 4^x * 4^y = 2^1^0 * 4^1^0 > 2^2^x * 4^y = 2^1^0 * 4^1^0\)
Now we have the same bases on the left and right side, so I can get rid of them:
\(2x * y = 10 * 10\)
By looking at the equation I concluded that x needs to be "5" (> 2*5=10) and y needs to be "10". Then the left side would equal the right side.
From (1) we get that the difference of x and y is 9. I figured that given my equation, we need a difference of 5 (x=5 and y=10 > difference between both is 5).
Can someone please help, if (i) my approach of simplifying the given equation was correct, and (ii) my train of thought is correct (apparently it is not)
Many thanks



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Re: Is 4^(x+y)=8^(10) ?
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21 Nov 2014, 04:47
mott wrote: Hi, could someone please help me evaluate my approach? I got stuck...
I did it this way:
\(4^x^+^y = 8^1^0 > 4^x * 4^y = 2^1^0 * 4^1^0 > 2^2^x * 4^y = 2^1^0 * 4^1^0\)
Now we have the same bases on the left and right side, so I can get rid of them:
\(2x * y = 10 * 10\)
By looking at the equation I concluded that x needs to be "5" (> 2*5=10) and y needs to be "10". Then the left side would equal the right side.
From (1) we get that the difference of x and y is 9. I figured that given my equation, we need a difference of 5 (x=5 and y=10 > difference between both is 5).
Can someone please help, if (i) my approach of simplifying the given equation was correct, and (ii) my train of thought is correct (apparently it is not)
Many thanks Yes, x + y must be 15 for \(4^{x+y}=8^{10}\) to hold true but it's not necessary that x = 10 and y = 5, there are many other solutions. For example, consider this if x = 0, then we'd have \(4^{y}=8^{10}\) > \(2^{2y}=2^{30}\) > y = 15. Or if x = 1, then we'd have \(4^{1+y}=8^{10}\) > \(2^{2+2y}=2^{30}\) > y = 14 ... Hope it helps.
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Re: Is 4^(x+y)=8^(10) ?
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05 Dec 2014, 13:34
Bunuel wrote: wutthiyo wrote: Bunuel wrote: Welcome to GMAT Club!
Actually the correct answer is C, not D.
From the stem the question became: is x + y = 15?
Now, (2) says that x  y = 9. Can we tell from this whether x + y = 15? No! Consider x = 10 and y = 1 for a NO answer and x = 12 and y = 3 for an YES answer. Hence, the first statement is NOT sufficient.
The same for the second statement.
The problem with your solution is that you assumed that we have two equations for each statement, whereas we have just one: x  y = 9 for (1) and y/x = 1/4 for (2). The second equation, x + y = 15 is not given to be true, we are asked to find whether it's true.
Hope it's clear.
Oh! Thanks a lot! That's clear. So when a question ask whether an equation is true or not, we cannot use it in solving the problem. Am I right? ^___^ Yes, you cannot use it as a given. Hi, just to add on to this for my understanding If the question had been asking for values of x & y, then A would be sufficient because we can plug it in



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Re: Is 4^(x+y)=8^(10) ?
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13 Aug 2015, 13:12
hi,
how is it not d? we can rewrite 4 ^ (x + y) to 2 ^ 2 * ( x + y ) and 8 ^ 10 to 2 ^ 30 2 ^ 2*(x+y) = 2^30 x+y=15 now statement 1 tells us xy=9 > therefore its solveable x=12 y=3; 2^2*15=2^30 same goes for statement 2.
so shouldnt it be d?



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Re: Is 4^(x+y)=8^(10) ?
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16 Aug 2015, 13:31
wercs wrote: hi,
how is it not d? we can rewrite 4 ^ (x + y) to 2 ^ 2 * ( x + y ) and 8 ^ 10 to 2 ^ 30 2 ^ 2*(x+y) = 2^30 x+y=15 now statement 1 tells us xy=9 > therefore its solveable x=12 y=3; 2^2*15=2^30 same goes for statement 2.
so shouldnt it be d? It is NOT give that \(4^{x+y}=8^{10}\). The question asks specifically about this: "is \(4^{x+y}=8^{10}\) ?"
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