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Pranjal3107
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Pranjal3107
chetan2u
Is 7 the hcf of p and q ?

1) p=7q+7=7(q+1)
If q is 1, 2 or 200, then yes.
But q could be a fraction too.
Insufficient

2) q is a multiple of 7
Nothing about p
Insufficient


Combined
So q=7x and p=7*7x+7=7(7x+1)
The HCF of two integers 7x and 7(7x+1) is 7.
Sufficient


C

But what if q=0 since 0 is a multiple of all numbers. In that case p=7 and q=0 ? Please help me where im going wrong.


If the two numbers are 0 and 7, then too the HCF will be 7.
0=0*1*2*..*7*….
7=1*7
Common factors: 1 and 7
Higher out of the two: 7
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Pranjal3107
chetan2u
Is 7 the hcf of p and q ?

1) p=7q+7=7(q+1)
If q is 1, 2 or 200, then yes.
But q could be a fraction too.
Insufficient

2) q is a multiple of 7
Nothing about p
Insufficient


Combined
So q=7x and p=7*7x+7=7(7x+1)
The HCF of two integers 7x and 7(7x+1) is 7.
Sufficient


C

But what if q=0 since 0 is a multiple of all numbers. In that case p=7 and q=0 ? Please help me where im going wrong.


If the two numbers are 0 and 7, then too the HCF will be 7.
0=0*1*2*..*7*….
7=1*7
Common factors: 1 and 7
Higher out of the two: 7

Oh wow did not know that. THANK YOU !!
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Pranjal3107. BrentGMATPrepNow
Can someone please explain how can the HCF of p & q be 7, if q=2?
p=7(3) = 21. so how can 7 be the HCF of 2 & 21?



chetan2u
Pranjal3107
chetan2u
Is 7 the hcf of p and q ?

1) p=7q+7=7(q+1)
If q is 1, 2 or 200, then yes.
But q could be a fraction too.
Insufficient

2) q is a multiple of 7
Nothing about p
Insufficient


Combined
So q=7x and p=7*7x+7=7(7x+1)
The HCF of two integers 7x and 7(7x+1) is 7.
Sufficient


C

But what if q=0 since 0 is a multiple of all numbers. In that case p=7 and q=0 ? Please help me where im going wrong.


If the two numbers are 0 and 7, then too the HCF will be 7.
0=0*1*2*..*7*….
7=1*7
Common factors: 1 and 7
Higher out of the two: 7
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Pranjal3107. BrentGMATPrepNow
Can someone please explain how can the HCF of p & q be 7, if q=2?
p=7(3) = 21. so how can 7 be the HCF of 2 & 21?



If q is 1, 2, 200, then the answer is yes as we know that the HCF is surely not 7, as p is a multiple of 7 and q is not.
However, when q is multiple of 7, p also becomes multiple of 7, and the answer is yes.

The second line in this has got missed in the answer.
Editing accordingly. Thanks.
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