Mohammad Ali Khan
Sorry m unable to get your explanation. Could you please elab.. how to approach these problems. Is \((9^x)^{3 – 2x} = 1\)?
\((9^x)^{3-2x}=(3^{2x})^{3-2x}=3^{2x(3-2x)}=1..\) Now, when can left hand side become 0.. ONLY when the exponent 2x(3-2x)=0.
That is \(3^{2x(3-2x)}=3^0..\)
Now, WHEN will 2x(3-x) be 0....When 2x =0, that is x=0 OR 3-2x=0, that is x=3/2.
So, the question finally becomes - Is x any one of 0 or 3/2.(1) The product of x and positive integer y is not x.\(xy\neq{x}......xy-x\neq{0}......x(y-1)\neq{0}\)... So, x is NOT 0, neither is y equal to 1.
If x=3/2 ans is yes, otherwise No.
Insuff
(2) x is a integer.Nothing much..
If x is 0, ans is yes, otherwise no..
Insuff
combined..
Now answer is yes, when x is 0 or 3/2, otherwise NO.Statement I tells us that
x is not 0, and statement II tells us that
x is not 3/2..
So, answer is NO.
Suff
C