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Is a^3-b^2>0?

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Is a^3-b^2>0? [#permalink]

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New post 06 May 2017, 20:39
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A
B
C
D
E

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Question Stats:

39% (01:03) correct 61% (00:59) wrong based on 90 sessions

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\(a^3 - b^2 > 0?\)
1. b > 0
2. a > |b|
[Reveal] Spoiler: OA

Last edited by chetan2u on 07 May 2017, 01:34, edited 1 time in total.
updated the OA
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Re: Is a^3-b^2>0? [#permalink]

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New post 06 May 2017, 21:39
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rajarshee wrote:
\(a^3 - b^2 > 0?\)
1. b > 0
2. a > |b|



Hi,

I do not think the answer should be B, it has to be E and this is WHY...
\(a^3-b^2>0\)...
Here b^2 will always be POSITIVE, so -b^2 will be NEGATIVE..
a^3 will depend on a...

Let's see the statements..
1) b>0..
We have b^2 which is always POSITIVE, so b >0 really doesn't help much..
Insufficient
2) a>|b|
This tells us that a is positive and also GREATER than numeric value of b..
If a >1, a^3 will be greater than b^2 and so ans will always be YES..
But if a is between 0 and 1, and will vary..
Say a=0.2 and b=0.1.....
Hence a>|b| but a^3=0.2^3=0.008 and b^2=0.1^2=0.01.... 0.01>0.008 or b^2>a^3
Now if a=0.9 and b=0.1 ....... a>|b| and a^3>b^2
So different answers
Insufficient..

Combined nothing new ..
Insufficient

E
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Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html


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Re: Is a^3-b^2>0? [#permalink]

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New post 06 May 2017, 21:42
IMHO B
Statement 1: b>0 doesn't tell anything about a. So insufficient.

Statement 2: a>|b| tells us a is positive and its value greater than absolute value of b.

Therefore a^2 >b^2 and since a is positive a^3>b^2
a^3-b^2>0
Sufficient
Ans B


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Re: Is a^3-b^2>0? [#permalink]

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New post 06 May 2017, 21:45
Clearly missed the a<1 scenario.
E is right

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Re: Is a^3-b^2>0? [#permalink]

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New post 07 May 2017, 19:46
Sorry folks, as you pointed out the answer provided was incorrect. Picked it up from a compiled set of questions in a pdf and so not a very reliable source for an answer.
Re: Is a^3-b^2>0?   [#permalink] 07 May 2017, 19:46
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