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# Is a < b? (1) a^3 = ab (2) |b| > |a|

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Re: Is a < b? (1) a^3 = ab (2) |b| > |a| [#permalink]
1
Kudos
it should be e

from 1st st. a can be 0 or a square can be equal to b
from 2nd, b can either be less than a or more than a
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Re: Is a < b? (1) a^3 = ab (2) |b| > |a| [#permalink]
Bunuel wrote:
Is a < b?

(1) a^3 = ab

(2) |b| > |a|

Source: 4Gmat

1) a^3=ab...
a(a^2-b)=0
So either a=0 or a^2=b or both are 0
Insufficient
2) |b|>|a|
So if b>0, yes a<b
If b<0, no
Insufficient

Combined..
We still can't say if b is positive or negative but b is not equal to 0..
Insufficient
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Re: Is a < b? (1) a^3 = ab (2) |b| > |a| [#permalink]
Answer would be E , I think.
a^3 = ab
a^2 = b

as bcz square can't be negative so b must be positive.
but a can be positve or negative so we can't decide. ( for taking 1 a can be equal to b or by taking any number b is always greater than a . )

| b | > | a |

b > a ( when taking + ve)

or

-b > -a ( when taking -ve )
b < a so we can't decide.
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Re: Is a < b? (1) a^3 = ab (2) |b| > |a| [#permalink]
Bunuel wrote:
Is a < b?

(1) a^3 = ab

(2) |b| > |a|

Source: 4Gmat

#1
a^3=ab
or say
a^2=b
now a= +/-2 and b=4
in sufficient
#2
|b| > |a|
we can have +/- values of b so in sufficient to conclude that b>a

from 1& 2
we cannot derive anything in common to conclude b>a
IMO E
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Re: Is a < b? (1) a^3 = ab (2) |b| > |a| [#permalink]
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Re: Is a < b? (1) a^3 = ab (2) |b| > |a| [#permalink]
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