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11 Nov 2015, 01:57
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C
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Difficulty:
25%
(medium)
Question Stats:
75% (01:34) correct
25%
(01:15)
wrong
based on 173
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Is a + b > 0 ?
(1) The point (a, b) is in Quadrant II.
(2) |a| - |b| > 0
(1) The point (a, b) is in Quadrant II.
(2) |a| - |b| > 0
11 Nov 2015, 02:03
Kudos
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Is a + b > 0 ?
(1) The point (a, b) is in Quadrant II.
In this quadrant we have negative x's and positive y's. Hence a < 0 and b > 0. This is not sufficient to say whether a + b > 0. Consider a = -1 and b = 2; and a = -2 and b = 1.
(2) |a| - |b| > 0 --> |a| > |b|. This implies that a is further from 0, on the number line, then b is. Also, not sufficient.
(1)+(2) Since from (1) a < 0 and b > 0, then for (2) we get -a - b > 0 --> a + b < 0. Sufficient.
Answer: C.
Hope it's clear.
(1) The point (a, b) is in Quadrant II.
In this quadrant we have negative x's and positive y's. Hence a < 0 and b > 0. This is not sufficient to say whether a + b > 0. Consider a = -1 and b = 2; and a = -2 and b = 1.
(2) |a| - |b| > 0 --> |a| > |b|. This implies that a is further from 0, on the number line, then b is. Also, not sufficient.
(1)+(2) Since from (1) a < 0 and b > 0, then for (2) we get -a - b > 0 --> a + b < 0. Sufficient.
Answer: C.
Hope it's clear.
11 Nov 2015, 17:26
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Bunuel
Is a + b > 0 ?
(1) The point (a, b) is in Quadrant II.
In this quadrant we have positive x's and negative y's. Hence a > 0 and b < 0. This is not sufficient to say whether a + b > 0. Consider a = 1 and b = -2; and a = 2 and b = -1.
(2) |a| - |b| > 0 --> |a| > |b|. This implies that a is further from 0, on the number line, then b is. Also, not sufficient.
(1)+(2) Since from (1) a > 0 and b < 0, then for (2) we get a - (-b) > 0 --> a + b > 0. Sufficient.
Answer: C.
Hope it's clear.
(1) The point (a, b) is in Quadrant II.
In this quadrant we have positive x's and negative y's. Hence a > 0 and b < 0. This is not sufficient to say whether a + b > 0. Consider a = 1 and b = -2; and a = 2 and b = -1.
(2) |a| - |b| > 0 --> |a| > |b|. This implies that a is further from 0, on the number line, then b is. Also, not sufficient.
(1)+(2) Since from (1) a > 0 and b < 0, then for (2) we get a - (-b) > 0 --> a + b > 0. Sufficient.
Answer: C.
Hope it's clear.
Hi Bunuel,
Please review highlighted part
In Statement 1, it says (a,b) in Quadrant II, x should be negative and y should be positive. so a<0 and b>0.
