Hi,
I have taken the following approach to solve this question. Please correct me if I am wrong.
Since it is a DS question, first we will have to simplify the question statement.
Is\( |a-b| < |a|+|b| ?\)
Squaring both sides, we will get.
Is \((|a-b|^2)<(|a|+|b|)^2 ?\)
Is \((a^2 - 2ab +b^2)<(a^2+2|a||b|+b^2)?\)
Since \(a^2\) and \(b^2\) will always be greater than equal to 0, so it will now affect the inequality sign. We can eliminate \(a^2\) and \(b^2\).
Is \((-2ab)<2|a||b| ?\)
On further simplification, we will get
Is \((-ab) < |a||b| ?\)
Now we know that \(|a||b| \)will always be positive or zero, .i.e
\(|a||b| >= 0\). i.e 0 would be the minimum possible value. So now we can replace \(|a||b|\) with 0 in the above equation. So now the question stem becomes :-
Is \((-ab) < 0?\)
Multiplying with -1 on both sides, the inequality sign will be reversed.
Is \(ab > 0 ?\)
So we have to check whether ab>0 or not or in other ways we have to check whether both a and b are of the same sign or not.
Now considering the statements.
Statement 1:- \(ab<0\)
So a and b are of opposite signs.
So from this statement, we are getting a definite answer to the question Is \(ab > 0?\)
This statement is sufficient.
We can eliminate options B, C, and E
Statement 2:- \(a^b < 0\)
This implies a is negative.
But don't know about the orientation of b.
If b is negative, then \(ab > 0\) and if b is positive, then \(ab < 0\).
So we are not getting a definite answer to the question Is \(ab < 0?\) from this statement.
This statement is insufficient. We can eliminate option D.
So IMO option A is the correct answer.