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Re: Is a > b − c? (1) c > b − a (2) b < c + a [#permalink]
Is a > b − c?

1. c > b - a
This can be rewritten as a > b - c (Sufficient)

2. b < c + a
This can be re-written as -a < c - b
Multiplying by -1, we get a > b - c (Sufficient - Option D)
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Re: Is a > b − c? (1) c > b − a (2) b < c + a [#permalink]
amanvermagmat wrote:
gmatexam439 wrote:
Bunuel wrote:
Is a > b − c?

(1) c > b − a
(2) b < c + a


Statement 1:
c>b-a
a>b-c --Sufficient

Statement 2:
b<c-a
a<c-b
-a>b-c --Since we don't know the sign of "a" we can't say anything. Insufficient

IMO answer should be "A"


Hi

I think the second statement says: b < c + a
So it becomes same as first statement


Yae. Thank you for pointing that out. I will update my post.
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Re: Is a > b − c? (1) c > b − a (2) b < c + a [#permalink]
in my opinion it's D
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Re: Is a > b c? (1) c > b a (2) b < c + a [#permalink]
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Re: Is a > b c? (1) c > b a (2) b < c + a [#permalink]
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