Dushyant20 wrote:
Wrong OA.
In 2. a+b = +- (c+d).
Posted from my mobile device
Hi Dushyant20,
The OA is correct, both statements are sufficient.
The question is \((a + b) < (c + d)\) ?
Or in other words \((a + b) - (c + d) < 0\) ?
The answer is NO, if left side is
equal to zero or
greater than 0
The answer is YES, if left side is
less than 0
Statement 2: \(a\) and \(b\) are positive integers such that \((a+b)^2−(c+d)^2=0\)
So \((a+b)^2−(c+d)^2=0\) and \((a+b) > 0\) while \((c+d)\) can be both
positive and
negativeFirst let \((c+d)\) be postive and , for example, equal to \(5\). For the equality in Statement 2 to be true \((a+b)\) should also be equal to \(5\)
Now answer the question whether \((a+b) - (c+d)<0\) ? Or is \(5 - 5\) less than \(0\)? The answer is NO because \(0\) is not less than \(0\).
Second let \((c+d)\) be negative and equal to \(-5\). Now \((a+b)\) is still positive according to Statement 2 and thus equal to \(5\).
Again answer the question whether \((a+b) - (c+d)<0\) ? Or is \(5 - (-5)\) less than \(0\)? The answer is again NO because 10 is not less than 0.
Thus, Statement 2 is
Sufficient.
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