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Statement# 1.

for a=0, we are getting 0<0, answer is no. Definitive sufficient answer.

Statement# 2.

for b=0, a might be -ve or +ve value.

0< -ve? yes, however 0<+ve ? no. Insufficinet.

Only A.

Bunuel
Is \(ab < a\)?

(1) \(a = 0\)
(2) \(b = 0\)
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Bunuel
Is \(ab < a\)?

(1) \(a = 0\)
(2) \(b = 0\)

Asked: ab < a?
a(b-1)< 0?

1)a = 0
Is 0 < 0?
No - Sufficient!
2)b = 0
-a < 0?
Case1:
a = 1, -1 < 0, Yes!
Case2:
a = -1, 1 < 0, No! - Insufficient!
IMO, (A)!
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Bunuel
Is \(ab < a\)?

(1) \(a = 0\)
(2) \(b = 0\)

IMO A

To check:
ab < a
ab - a < 0
a(b-1)<0

To check a<0 or b<1, Also you can compare with 'a' only if we know value of 'a'
So, a<0
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