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21 Mar 2017, 05:44
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
55% (01:58) correct
45%
(01:31)
wrong
based on 42
sessions
History
Date
Time
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Not Attempted Yet
21 Mar 2017, 06:32
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Bunuel
Is ab – c > 0?
(1) ab/c < 1
(2) abc > 0
(1) ab/c < 1
(2) abc > 0
Question: Is ab > c ?
(1) ab/c <1 - Not sufficient.
a=2, b=2, c=8 - No
a=2, b=2, c=-2 - Yes
(2) abc > 0 - Not sufficient.
a=1, b=1, c=1 - No
a=2, b=3, c=4 - Yes
(1) + (2) - Not sufficient
a=-1, b=1,c=-2 - Yes
a=2,b=2,c=5 - No
Hence E.
Cheers!
21 Mar 2017, 08:25
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Bunuel
Is ab – c > 0?
(1) ab/c < 1
(2) abc > 0
(1) ab/c < 1
(2) abc > 0
Is ab – c > 0? or say is ab > c?
(1) ab/c < 1
It means numerator is less than denomenator. hence ab < c. this is a trap. Because less than one also have negative values. and we do not know sign of a, b & c.
Insufficient.
(2) abc > 0
All a, b & c could be +ve or two of these variables could be -ve and one could be +ve. With this again it is hard to say anything about sign of a, b & c.
Insufficient.
Combining 1 & 2:
ab/c < 1 and abc > 0
we again do not know about signs.
if a & c are -ve and b is +ve then ab > c
if a & b are -ve and c is +ve then ab < c
Answer is E.
