Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
vitorpteixeira
GMAT 1: 610 Q45 V28
Posts: 24
04 Oct 2017, 10:27
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
52% (01:28) correct
48%
(01:16)
wrong
based on 48
sessions
History
Date
Time
Result
Not Attempted Yet
Is cone P similar to cone Q?
(1) The surface area of P is 9 times the surface area of Q
(2) The volume of P is 9 times the volume of Q
(1) The surface area of P is 9 times the surface area of Q
(2) The volume of P is 9 times the volume of Q
06 Oct 2017, 07:55
Kudos
Bookmarks
vitorpteixeira
HI..
with 100% answering incorrectly, this may help
thing to remember..
Two cones will be similar when the RADIUS and the HEIGHT are in SAME proportion
so \(\frac{R_P}{R_Q}=\frac{H_P}{H_Q}=k\)
let's see the statements
(1) The surface area of P is 9 times the surface area of Q
this means \(9*pi*R_P^2+pi*R_P*\sqrt{H_P^2+R_P^2}=pi*R_Q^2+pi*R_Q*\sqrt{H_Q^2+R_Q^2}\)..
so \(9*=pi*R_P^2+pi*R_P*\sqrt{H_P^2+R_P^2}/pi*R_Q^2+pi*R_Q*\sqrt{H_Q^2+R_Q^2}=(R_P^2+R_P*\sqrt{H_P^2+R_P^2})/(R_Q^2+R_Q*\sqrt{H_Q^2+R_Q^2})\)
two cases..
if similar, the ratio \(k = \sqrt{9}=3\)... Possible
or it can be various combination to get the ratio as 9...Possible
Insuff
(2) The volume of P is 9 times the volume of Q
\(\frac{1}{3}*pi*R_P^2H_P=9*\frac{1}{3}*pi*R_Q^2H_Q............\frac{R_P^2H_P}{R_Q^2H_Q}=9\)..
two cases
1) if \(k^3=9\) .. similar possible
2) only \(R_P=3*R_Q\)... not similar.. possible
so insuff..
combined..
different values of k in both cases so the cones are NOT similar
Sufficient
C
03 Aug 2023, 23:02
Kudos
Bookmarks
Automated notice from GMAT Club BumpBot:
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
This post was generated automatically.
