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# [[x]] is equal to the lesser of the two integer values closest to non-

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Joined: 02 Sep 2009
Posts: 47977
[[x]] is equal to the lesser of the two integer values closest to non-  [#permalink]

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15 Apr 2015, 04:21
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25
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Difficulty:

95% (hard)

Question Stats:

38% (01:48) correct 62% (01:29) wrong based on 361 sessions

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[[x]] is equal to the lesser of the two integer values closest to non-integer x. What is the absolute value of $$[[-\pi]] + [[-\sqrt{37}]]$$ ?

(A) [[9.4]]

(B) [[4 pi]]

(C) $$[[\sqrt{99}]]$$

(D) $$[[\sqrt{120}]]$$

(E) $$[[\sqrt{143}]]$$

Kudos for a correct solution.

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Re: [[x]] is equal to the lesser of the two integer values closest to non-  [#permalink]

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15 Apr 2015, 08:24
4
Bunuel wrote:
[[x]] is equal to the lesser of the two integer values closest to non-integer x. What is the absolute value of $$[[-\pi]] + [[-\sqrt{37}]]$$ ?

(A) [[9.4]]

(B) [[4 pi]]

(C) $$[[\sqrt{99}]]$$

(D) $$[[\sqrt{120}]]$$

(E) $$[[\sqrt{143}]]$$

Kudos for a correct solution.

pi=3.14
-pi=-3.14
Lesser of the 2 integers closest to -3.14 is -4

$$\sqrt{37}$$=6.1 (approx)
Lesser of the 2 integers closest to -6.1 is -7

-4 + -7 = -11
|-11|=11

Option E:
$$\sqrt{143}$$= Little less than 12 or 11.9
Lesser of the 2 integers closest to 11.9 is 11

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Joined: 01 Jan 2015
Posts: 56
Re: [[x]] is equal to the lesser of the two integer values closest to non-  [#permalink]

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15 Apr 2015, 14:58
[[-3.14]] = -4 (lesser of the two{-3 and -4}= -4)
[[-(Sqroot37)]] = -7 (lesser of the two{-6 and -7}= -7)
Adding both -4-7 = -11 ;Absolute value = 11

E = [[(Sqroot143)]] = 11 (lesser of the two{11 and 12}= 11

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Re: [[x]] is equal to the lesser of the two integer values closest to non-  [#permalink]

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23 Aug 2016, 09:25
Bunuel wrote:
[[x]] is equal to the lesser of the two integer values closest to non-integer x. What is the absolute value of $$[[-\pi]] + [[-\sqrt{37}]]$$ ?

(A) [[9.4]]

(B) [[4 pi]]

(C) $$[[\sqrt{99}]]$$

(D) $$[[\sqrt{120}]]$$

(E) $$[[\sqrt{143}]]$$

Kudos for a correct solution.

"[[x]] is equal to the lesser of the two integer values closest to non-integer x " can be interpreted as floor(x) or round-down of x.
i.e if $$x= 3.9, [[x]] = 3$$ and if$$x=-3.1, [[x]] = -4$$
so $$[[-\pi]] + [[-\sqrt{37}]]$$ = $$[[-3.14] + [[-6.something]]$$ = $$-4 + -7$$ = $$-11$$

And absolute value is 11. Only E has the value when rounded down equals to 11.

+1 for kudos
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Joined: 12 Sep 2015
Posts: 2705
Re: [[x]] is equal to the lesser of the two integer values closest to non-  [#permalink]

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26 Aug 2016, 08:13
1
Top Contributor
3
Bunuel wrote:
[[x]] is equal to the lesser of the two integer values closest to non-integer x. What is the absolute value of $$[[-\pi]] + [[-\sqrt{37}]]$$ ?

(A) [[9.4]]

(B) [[4 pi]]

(C) $$[[\sqrt{99}]]$$

(D) $$[[\sqrt{120}]]$$

(E) $$[[\sqrt{143}]]$$

Kudos for a correct solution.

[[−pi]]
[[−pi]] = [[−3.14]] = -4, since -4 < -3.14 < -3, and -4 is the lesser of -4 and -3

[[−√37]]
Notice that √36 = 6 and √49 = 7, so √37 = 6.something
So, [[−√37]] = [[−6.something]] = -7, since -7 < −6.something < -6, and -7 is the lesser of -7 and -6

So, [[−pi]] + [[−√37]] = (-4) + (-7) = -11
This means the ABSOLUTE VALUE of [[−pi]] + [[−√37]] = |-11| = 11

NOTE: this is one of those questions that require us to check/test each answer choice. In these situations, always check the answer choices from E to A, because the correct answer is typically closer to the bottom than to the top. For more on this strategy, see my article: http://www.gmatprepnow.com/articles/han ... -questions

E) [[√143]]
Notice that √121 = 11 and √144 = 12, so √143 = 11.something
So, [[√143]] = [[11.something]] = 11 [ since 11 < 11.something < 12, and 11 is the lesser of 11 and 12

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Re: [[x]] is equal to the lesser of the two integer values closest to non-  [#permalink]

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26 Oct 2017, 13:21
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Re: [[x]] is equal to the lesser of the two integer values closest to non- &nbs [#permalink] 26 Oct 2017, 13:21
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