Is integer y > 0? (1) (2 + y) > 0 (2) (2 + y)^2 > 0

It's A, since y should be less than 0 for the -(2+y)>0.

For ST2 ycan take either +ve or -ve y.

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Statement 1:

–(2 + y) > 0
=> 2+y < 0
=> y<-2. Hence, A is sufficient.

Statement 2: whether y is +ve or -ve, this statement will always be positive. Hence , INSUFFICIENT.
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Target question: Is integer y GREATER THAN 0?

Statement 1: –(2 + y) > 0
Expand to get: –2 - y > 0
Add y to both sides to get: -2 > y
If y is LESS than -2, we can be certain that y is NEGATIVE.
This means we can conclude that y is definitely not greater than 0
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: (2 + y)² > 0
Hmmm, the square of some value is ALWAYS greater than or equal to zero. So, this statement doesn't seem to tell us much.
Since this statement doesn't FEEL sufficient, I'll TEST some values.
There are several values of y that satisfy statement 2. Here are two:
Case a: y = 1. Here, (2 + y)² = (2 + 1)² = 9, and 9 > 0. In this case, y is GREATER THAN 0
Case b: y = -1. Here, (2 + y)² = (2 + -1)² = 1, and 1 > 0. In this case, y is NOT greater than 0
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer =

Aside: For more on this idea of plugging in values when a statement doesn't feel sufficient, you can read my article: https://www.gmatprepnow.com/articles/dat ... lug-values

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(1) –(2 + y) > 0
2+y <0
y<-2. This means that y is not >0

Sufficient.

(2) (2 + y)^2 > 0
(2 + y) > 0
y>-2

so y can be -1, 0 , 1. Not sufficient.

A is the answer
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For statement 2, we have (2+y)^2 > 0 and you have tested for the positive value of (2+y). Theoretically, do we need to test for (2+y)<0 also?

The question asks if y > 0.

Statement-1 states that –(2 + y) > 0
We know that when we multiply with -1 in an inequality the sign changes.
Hence 2+y <0
or we get y<-2.
And hence y >0 is false.
Or, Statement is Sufficient.

Cancel BCE. Keep AD.

Statement-2 states that (2 + y)^2 > 0
But square of anything will always be greater than zero.
Hence if we plug in with y=-1 or y=1, we also get the same result.
In other words y can be negative or positive.
Hence Insufficient.

Cancel D. Right Option is A.

As per statement 1, you can see that if you plug any value of y<-2, the inequality will hold true.
So, the first statement makes it clear that y<-2 and not y>0, as being questioned.

Therefore, SUFFICIENT.

However, as per the second statement, the value on the LHS will always be true for any real value of y. Therefore, Statement 2 is NOT SUFFICIENT.

Hence, the answer is A.

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