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Sunny143
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Sunny143
Is n/18 an integer?

(1) 5n/18 is an integer

(2) 3n/18 is an integer.

I think the quesiton stem should include - n is an integer - or something like that.
if such info is actually present then it is A!

if not, then it is E, and the question would fall into the "cheap trick" category.... yuck!
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Sunny143
Is n/18 an integer?

(1) 5n/18 is an integer

(2) 3n/18 is an integer.

I think the quesiton stem should include - n is an integer - or something like that.
if such info is actually present then it is A!

if not, then it is E, and the question would fall into the "cheap trick" category.... yuck!

The question is from MGMAT...and there is no information missing....try to solve the problem rather than giving comments like the "cheap trick" category.... yuck ...this is totally uncalled for....

In fact E is not the OA. Thanks
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Sunny143
anirudhoswal
Sunny143
Is n/18 an integer?

(1) 5n/18 is an integer

(2) 3n/18 is an integer.

I think the quesiton stem should include - n is an integer - or something like that.
if such info is actually present then it is A!

if not, then it is E, and the question would fall into the "cheap trick" category.... yuck!

The question is from MGMAT...and there is no information missing....try to solve the problem rather than giving comments like the "cheap trick" category.... yuck ...this is totally uncalled for....

In fact E is not the OA. Thanks

Hey.. don't take it personally man.
I did solve the question. Only, trying to illustrate that this problem is not really based on mathematical concepts... it is designed to catch you off-guard during the test.
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I will go with A
(1) 5n/18 is an integer. Since 5/18 is not an integer so n must be divisible by 18.
Sufficient
(2) 3n/18 is an integer. say n=6 then 3*6=18 is divisible by 18 but 6/18 is not an integer.
Insufficient
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ritula
I will go with A
(1) 5n/18 is an integer. Since 5/18 is not an integer so n must be divisible by n.
Sufficient
(2) 3n/18 is an integer. say n=6 then 3*6=18 is divisible by 18 but 6/18 is not an integer.
Insufficient

A should not be OA, If n=18/5, 5n/18 is integer, but n/18 is not integer :-D

If not E, C should be OA. I am tired of..!
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OA is C.

This is the OE from MGMAT:

(1) INSUFFICIENT: We are told that 5n/18 is an integer. This does not allow us to determine whether n/18 is an integer. We can come up with one example where 5n/18 is an integer and where n/18 is NOT an integer. We can come up with another example where 5n/18 is an integer and where n/18 IS an integer.

Let's first look at an example where 5n/18 is equal to the integer 1.
If 5n/18 = 1, then n/18 = 1/5 . In this case n/18 is NOT an integer.

Let's next look at an example where 5n/18 is equal to the integer 15.

If 5n/18 = 15, then n/18 = 3 . In this case n/18 IS an integer.

Thus, Statement (1) is NOT sufficient.

(2) INSUFFICIENT: We can use the same reasoning for Statement (2) that we did for statement (1). If 3n/18 is equal to the integer 1, then n/18 is NOT an integer. If 3n/18 is equal to the integer 9, then n/18 IS an integer.

The first possible value of n is 18, since this is the first value of n that ensures that both 5n/18 and 3n/18 are integers. If n = 18, then n/18 is an integer. Another possible value of n is 36. (This value also ensures that both 5n/18 and 3n/18 are integers). If n = 36, then n/18 is an integer.

(1) AND (2) SUFFICIENT: If 5n/18 and 3n/18 are both integers, n/18 must itself be an integer. Let's test some examples to see why this is the case.

A pattern begins to emerge: the fact that 5n/18 AND 3n/18 are both integers limits the possible values of n to multiples of 18. Since n must be a multiple of 18, we know that n/18 must be an integer. The correct answer is C.

Another way to understand this solution is to note that according to (1), n = (18/5)*integer, and according to (2), n = 6*integer. In other words, n is a multiple of both 18/5 and 6. The least common multiple of these two numbers is 18. In order to see this, write 6 = 30/5. The LCM of the numerators 18 and 30 is 90. Therefore, the LCM of the fractions is 90/5 = 18.

Again, the correct answer is C.
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Sunny143
OA is C.

This is the OE from MGMAT:

(1) INSUFFICIENT: We are told that 5n/18 is an integer. This does not allow us to determine whether n/18 is an integer. We can come up with one example where 5n/18 is an integer and where n/18 is NOT an integer. We can come up with another example where 5n/18 is an integer and where n/18 IS an integer.

Let's first look at an example where 5n/18 is equal to the integer 1.
If 5n/18 = 1, then n/18 = 1/5 . In this case n/18 is NOT an integer.

Let's next look at an example where 5n/18 is equal to the integer 15.

If 5n/18 = 15, then n/18 = 3 . In this case n/18 IS an integer.

Thus, Statement (1) is NOT sufficient.

(2) INSUFFICIENT: We can use the same reasoning for Statement (2) that we did for statement (1). If 3n/18 is equal to the integer 1, then n/18 is NOT an integer. If 3n/18 is equal to the integer 9, then n/18 IS an integer.

The first possible value of n is 18, since this is the first value of n that ensures that both 5n/18 and 3n/18 are integers. If n = 18, then n/18 is an integer. Another possible value of n is 36. (This value also ensures that both 5n/18 and 3n/18 are integers). If n = 36, then n/18 is an integer.

(1) AND (2) SUFFICIENT: If 5n/18 and 3n/18 are both integers, n/18 must itself be an integer. Let's test some examples to see why this is the case.

A pattern begins to emerge: the fact that 5n/18 AND 3n/18 are both integers limits the possible values of n to multiples of 18. Since n must be a multiple of 18, we know that n/18 must be an integer. The correct answer is C.

Another way to understand this solution is to note that according to (1), n = (18/5)*integer, and according to (2), n = 6*integer. In other words, n is a multiple of both 18/5 and 6. The least common multiple of these two numbers is 18. In order to see this, write 6 = 30/5. The LCM of the numerators 18 and 30 is 90. Therefore, the LCM of the fractions is 90/5 = 18.

Again, the correct answer is C.

Okay.. I feel like taking all my comments back now. Good question sunny143.
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Sunny143
Is n/18 an integer?

(1) 5n/18 is an integer

(2) 3n/18 is an integer.

Very good question Sunny

this one got me.

was just tricked by A

newaz just need to be more careful
thanks for posting this ...kudos to u



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