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divakarbio7
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divakarbio7
Is N divisible by 7?

1> N=x-y, where x & y are integers
2> x is divisible by 7, & y is not divisible by 7.

DS questions of this kind demand a substantial answer, a strong YES or NO. If you can prove either of them based on the two given statements, you have nailed the question. Here, both the statements are required to prove strongly that N can never be divisible by 7. That's it - PERIOD!!
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Thank you all :-D
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Is N divisible by 7?

1> N=x-y, where x & y are integers = x and y can be any value. insufficient.
2> x is divisible by 7, & y is not divisible by 7 = using this no connection to N.

BOTH = let's take x=7 & y=3
therefore, N=x-y=1-3 = N is not divisible by 7
if x=7 and y= 7 = N=0/7 not divisible. So, taking any value using both it does not satisfy that N/7.
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divakarbio7
Is N divisible by 7?

1> N=x-y, where x & y are integers
2> x is divisible by 7, & y is not divisible by 7.

The answer is c, its say's by combining we can say x is the multiple of 7, but y is not multiple of 7. The difference between x & y NEVER be divisible by 7 if x is divisible by 7 but y is not ( this part I am unable to understand :( - is there some rule that i need to learn here or a logic to follow)

Regards
Divakar KN
:flower

Easiest way....

S1 alone is not sufficient as no idea abt x and y
S2 alone is not sufficient.. as no relation with N
Hence either C or E...
N=x-y and x is divisible by 7 and y is not...

\(\frac{N}{7}=\frac{x-y}{7}=\frac{x}{7}-\frac{y}{7}=\) Integer (as X is divisble by 7) - non integer (fraction as y is not divisible by 7) = non integer.

Hence not divisible. Therefore C.



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