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10 Dec 2018, 03:55
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
66% (01:46) correct
34%
(01:30)
wrong
based on 145
sessions
History
Date
Time
Result
Not Attempted Yet
eswarchethu135
GMAT 2: 640 Q49 V27
Posts: 276
10 Dec 2018, 04:17
Kudos
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(1) \(\frac{p}{(p + q)}\) > 0
Consider p = 1 and q = 1
\(\frac{p}{p+q}\) = \(\frac{1}{2}\)>0
P+Q > 0 YES
Consider p = -1 and q = -1
\(\frac{p}{p+q}\) = \(\frac{-1}{-2}\)>0
P+Q > 0 NO
INSUFFICIENT
(2) \(\frac{q}{(p + q)}\) > 0
Consider p = 1 and q = 1
\(\frac{q}{p+q}\) = \(\frac{1}{2}\)>0
P+Q > 0 YES
Consider p = -1 and q = -1
\(\frac{q}{p+q}\) = \(\frac{-1}{-2}\)>0
P+Q > 0 NO
INSUFFICIENT
1) + 2) still the same result for both the choices.
OPTION: E
Consider p = 1 and q = 1
\(\frac{p}{p+q}\) = \(\frac{1}{2}\)>0
P+Q > 0 YES
Consider p = -1 and q = -1
\(\frac{p}{p+q}\) = \(\frac{-1}{-2}\)>0
P+Q > 0 NO
INSUFFICIENT
(2) \(\frac{q}{(p + q)}\) > 0
Consider p = 1 and q = 1
\(\frac{q}{p+q}\) = \(\frac{1}{2}\)>0
P+Q > 0 YES
Consider p = -1 and q = -1
\(\frac{q}{p+q}\) = \(\frac{-1}{-2}\)>0
P+Q > 0 NO
INSUFFICIENT
1) + 2) still the same result for both the choices.
OPTION: E
Updated on: 10 Dec 2018, 15:04
Originally posted by shinichikudo on 10 Dec 2018, 05:32.
Last edited by shinichikudo on 10 Dec 2018, 15:04, edited 1 time in total.
Last edited by shinichikudo on 10 Dec 2018, 15:04, edited 1 time in total.
Kudos
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(DS) Yes/ No question
Is p+q > 0 ?
(1) p/(p + q) > 0
We have 4 possibilities :
* p>0 , (p+q) >0 => p/(p + q) > 0 (yes)
* p<0 , (p+q) >0 => p/(p + q) < 0 (no)
* p>0 , (p+q)< 0 => p/(p + q) < 0 (no)
* p<0 , (p+q) <0 => p/(p + q) > 0 (yes)
=> ns => B/C/E
(2) q/(p + q) > 0
Same as (1) => ns => C/E
(1) + (2) : p/(p + q) + q/(p + q) > 0
<=>(p+q)/(p+q) > 0, we have 2 possibilities :
*(p+q) >0 and (p+q) >0 => (p+q)/(p+q) > 0 (yes)
*-(p+q) <0 and (p+q) >0 => (p+q)/(p+q) < 0 (no)
=> ns => Answer E
Is p+q > 0 ?
(1) p/(p + q) > 0
We have 4 possibilities :
* p>0 , (p+q) >0 => p/(p + q) > 0 (yes)
* p<0 , (p+q) >0 => p/(p + q) < 0 (no)
* p>0 , (p+q)< 0 => p/(p + q) < 0 (no)
* p<0 , (p+q) <0 => p/(p + q) > 0 (yes)
=> ns => B/C/E
(2) q/(p + q) > 0
Same as (1) => ns => C/E
(1) + (2) : p/(p + q) + q/(p + q) > 0
<=>(p+q)/(p+q) > 0, we have 2 possibilities :
*(p+q) >0 and (p+q) >0 => (p+q)/(p+q) > 0 (yes)
*-(p+q) <0 and (p+q) >0 => (p+q)/(p+q) < 0 (no)
=> ns => Answer E
