Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem.
Remember equal number of variables and independent equations ensures a solution.
Is t^2 > t/3?
(1) t > 0
(2) |t| > 1/3
in case of inequality questions we're not going to simply substitute all the values, but we'll be comparing the range of que and the range of con and see if the range of que includes that of con. If it does, then the condition is sufficient.
Transforming the original condition, we have t^2-t/3>0?, t(t-1/3)>0? gives us t<0, 1/3<t?. Since there is 1 variable, we need 1 equation and there is 1 each in 1) and 2). therefore D has high probability of being the answer.
In case of 1), t>0 does not make the range of que include the range of con. Therefore the condition is not sufficient.
In case of 2), t<-1/3, 1/3<t and thus the range of que includes the range of con. Therefore the condition is sufficient and the answer is B.
Normally for cases where we need 1 more equation, such as original conditions with 1 variable, or 2 variables and 1 equation, or 3 variables and 2 equations, we have 1 equation each in both 1) and 2). Therefore D has a high chance of being the answer, which is why we attempt to solve the question using 1) and 2) separately. Here, there is 59 % chance that D is the answer, while A or B has 38% chance. There is 3% chance that C or E is the answer for the case. Since D is most likely to be the answer according to DS definition, we solve the question assuming D would be our answer hence using 1) and 2) separately. Obviously there may be cases where the answer is A, B, C or E.
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