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JayPatadiya
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This question is absolutely not GMAT-like. GMAC won't ask with such specific term "arithmetic progression".

Don't bother to answer the question

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IanStewart I missed the subtle case. Thanks for the explanation.

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JayPatadiya
Is the 22nd term of an Arithmetic Progression odd?
1. The 24th tern is even
2. The first term is odd

The OA is given as A here, which is not correct. Using only Statement 1, the 22nd, 23rd and 24th terms of the sequence could be, say

22, 23, 24

in which case the 22nd term is even, but they could also be

21, 22.5, 24

in which case the 22nd term is odd.

As the question is written, the answer is C, since with both statements you can be certain the 22nd term is not odd. If you pretend the 22nd term is odd, you can see you'll reach a contradiction. If the list goes up by d from one term to the next:

- if the 22nd and 24th terms are integers in an equally spaced list, then 2d must be an integer, and every term in an even position in the sequence must be an integer
- so the 2nd term would then be an integer
- but we know the first term is an integer too, and if the 1st and 2nd terms are integers, every term is an integer, and the spacing d is an integer
- but then the 22nd and 24th terms would need to both be even or both be odd, since they are 2d apart. But they're not both even or both odd, so this entire situation is impossible.

So it's impossible, using both Statements, for the 22nd term to be odd, and the answer is C. The reasoning here is probably a lot more complicated than the question designer intended, if the question designer believed the answer was A. The answer is only A if the question tells you the terms in the sequence are integers.
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JayPatadiya
Is the 22nd term of an Arithmetic Progression odd?

1. The 24th tern is even
2. The first term is odd

Solution:
Pre Analysis:
  • We are asked if the 22nd term of an AP is odd or not
  • This is a YES-NO question

Statement 1: The 24th tern is even
  • We know \(T_{22}=T_{24}-2d\) where d is the common difference
  • So, \(T_{22}=Even-Even=Even\)
  • Thus, statement 1 alone is sufficient and we can eliminate options B, C and E

Statement 2: The first term is odd
  • We know \(T_{22}=T_{1}+21d\)
  • So, \(T_{22}=Odd+21d\)
  • To predict the even-odd nature of \(T_{22}\), we will need the even-odd nature of \(d\)
  • Thus, statement 2 alone is not sufficient


Hence the right answer is Option A
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SaquibHGMATWhiz
JayPatadiya
Is the 22nd term of an Arithmetic Progression odd?

1. The 24th tern is even
2. The first term is odd

Solution:
Pre Analysis:
  • We are asked if the 22nd term of an AP is odd or not
  • This is a YES-NO question

Statement 1: The 24th tern is even
  • We know \(T_{22}=T_{24}-2d\) where d is the common difference
  • So, \(T_{22}=Even-Even=Even\)
  • Thus, statement 1 alone is sufficient and we can eliminate options B, C and E

Statement 2: The first term is odd
  • We know \(T_{22}=T_{1}+21d\)
  • So, \(T_{22}=Odd+21d\)
  • To predict the even-odd nature of \(T_{22}\), we will need the even-odd nature of \(d\)
  • Thus, statement 2 alone is not sufficient


Hence the right answer is Option A

How can we be sure that d is an integer ?
if d=1/2.

IMO: Answer should be C.
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Nabneet
SaquibHGMATWhiz
JayPatadiya
Is the 22nd term of an Arithmetic Progression odd?

1. The 24th tern is even
2. The first term is odd

Solution:
Pre Analysis:
  • We are asked if the 22nd term of an AP is odd or not
  • This is a YES-NO question

Statement 1: The 24th tern is even
  • We know \(T_{22}=T_{24}-2d\) where d is the common difference
  • So, \(T_{22}=Even-Even=Even\)
  • Thus, statement 1 alone is sufficient and we can eliminate options B, C and E

Statement 2: The first term is odd
  • We know \(T_{22}=T_{1}+21d\)
  • So, \(T_{22}=Odd+21d\)
  • To predict the even-odd nature of \(T_{22}\), we will need the even-odd nature of \(d\)
  • Thus, statement 2 alone is not sufficient


Hence the right answer is Option A

How can we be sure that d is an integer ?
if d=1/2.

IMO: Answer should be C.

Hey Nabneet,

Thank you for pointing it out. I completely missed out on this constraint.
Apart from that, this question is a little complicatedly designed and is well explained by IanStewart.
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How do we know the common difference is an integer?
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The answer should be E. Let the first term as A and common difference as D, pl note it's not given that d is an interger!

Statement 1 - Not suffucient as combo of 1st term and common difference can be (odd,odd) or (even,even)
Statement 2 - Not suffucient as combo of 1st term and common difference can be (odd,odd), (odd,even).

Combining, A can be odd and D can be (some odd number/23) => 24rd term is even but 22nd is not, in other case, A can be odd and D can be some odd integer => both. 24th and 22nd term will be even. Not sufficent.

What am I mssing?
JayPatadiya
Is the 22nd term of an Arithmetic Progression odd?

1. The 24th tern is even
2. The first term is odd

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Nothing, you are spot on. Nowhere is it specified that any of the integers between 1st and 22nd term have to be integer, nor that the difference has to be an integer.
2407adi
The answer should be E. Let the first term as A and common difference as D, pl note it's not given that d is an interger!

Statement 1 - Not suffucient as combo of 1st term and common difference can be (odd,odd) or (even,even)
Statement 2 - Not suffucient as combo of 1st term and common difference can be (odd,odd), (odd,even).

Combining, A can be odd and D can be (some odd number/23) => 24rd term is even but 22nd is not, in other case, A can be odd and D can be some odd integer => both. 24th and 22nd term will be even. Not sufficent.

What am I mssing?


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