Answer is "
C".
This question can be solved using cosine formula: \(c^2 = a^2 + b^2 -2abCosC\)
Statement 1: The length of PQ is twice the length of RQ.
This information alone is not sufficient for us to find the value of
a. We need more information.
Statement 2: angle b = 60 deg
This information alone is not sufficient for us to determine
a. We need more information.
Both Statement Together: The length of PQ is twice the length of RQ and angle b = 60 deg
This information seems enough for us to determine the value of angle P and state if it is \(30^{\circ}\)
Let the sides opposite to angle P, Q, R be p, q and r respectively.
Given: From Statement 1 & 2, r = 2p and b = \(60^{\circ}\)
Step 1: Using cosine formula for
b (Angle Q),
\(q^2 = p^2 + r^2 - 2prCos(b)\)
Replacing values of r and Q from given, we get (Cos 60 = 1/2)
\(q^2 = 3p^2\) or, \(q = \sqrt{3}p\)
Step 2: Now using Cosine formula for
a (Angle P),
\(p^2 = q^2 + r^2 - 2qrCos(a)\)
Replacing values for r and q from given and Step 1, we get
\(Cos(a) = \sqrt{3}/2\)
Therefore, a = \(30^{\circ}\)
Based on information provided in both statements, we can conclude that the angle
a is indeed \(30^{\circ}\).
Therefore, Answer is
C (Both Statements (1) and (2) TOGETHER are sufficient to answer the question asked; but NEITHER statement ALONE is sufficient)